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3 years ago

8y-8(y-1)=6-(16y-4)-10 Solve the linear equation ?

Mathematics

1 answer:

slamgirl [31]3 years ago

6 0

Answer:

y = -1/2

Step-by-step explanation:

First distribute.

8y - 8y + 8 = 6 - 16y + 4 - 10

8 = -16y

Divide by -16.

y = -1/2

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Answer:

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Step-by-step explanation:

Given

$S_n = n^2 -2n$

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Solving (a): T7

Substitute 7 for n in $T_n = S_n - S_{n-1}$

$T_7 = S_7 - S_{7-1}$

$T_7 = S_7 - S_6$

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Solving (b): Tn

$T_n = S_n - S_{n-1}$

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Calculate $S_{n-1}$

We have:

$S_{n-1} =(n-1)^2 - 2(n-1)$

Open brackets

$S_{n-1} = n^2 -2n + 1 -2n +2$

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So:

$T_n = S_n - S_{n-1}$

$T_n = n^2 - 2n - (n^2 -4n + 3)$

$T_n = n^2 - 2n - n^2 +4n - 3$

Collect Like Terms

$T_n = n^2 - n^2- 2n +4n - 3$

$T_n = 2n- 3$

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