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scZoUnD [109]
3 years ago
13

The value of a car decreases by 5% each year.

Mathematics
1 answer:
madreJ [45]3 years ago
6 0
10,000*0.95^2
=9025

0.95 is a multiplyer since 100%-5%=95% then divided by 100 giving you 0.95

You always power by the amount of years

So the format is always
Amount*multiplyer^years
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Miguel and Kat are reading the same book. Miguel reads 5 times as many
n200080 [17]

Answer:

k=\dfrac{m}{5}

Step-by-step explanation:

Let Kat reads k pages of the book.

Miguel reads 5 times as many  pages of the book as Kat. So,

m = 5k ...(1)

Together they read 54 pages. i.e.

m+k = 54 ...(2)

From equation (1),

k=\dfrac{m}5{}

Hence, the equation that can be used to find how many pages Kat read is equal to \dfrac{m}{5}.

6 0
2 years ago
Plz help me this one is a lil tough
Aneli [31]

Answer:

100 degrees

Step-by-step explanation:

It's going through 140 and 40, 180 - 40 = 140

180 cause a flat line is 180 degrees

8 0
3 years ago
Read 2 more answers
Sasha hikes into a canyon. She takes a break at the rest stations every 2/3 of a mile. If she started at sea level and has hiked
butalik [34]

the only right one is a, hope this helps

6 0
3 years ago
1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.
xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}

(If you were to plot the actual curve, you would have both y=x^{2/3} and y=-x^{2/3}, but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx

We have

y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}

Then in the integral,

\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx

Substitute

u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx

This transforms the integral to

\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du

and computing it is trivial:

\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)

We can simplify this further to

\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}

7 0
3 years ago
(50 points)<br><br><br><br> NEED ANSWER ASAPPPP:)
lbvjy [14]
5-10(|0.8-3/6|)

5-10(|1/5|)

5-(10)(0.2)

5-2

=3, so C would be your best answer. 
5 0
3 years ago
Read 2 more answers
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