How to solve p-10/-2=0

Tanya [424]

Answer:

Ok listen here

Step-by-step explanation:

You are like the earth.

On the inside is a bright center and lava. When lava comes to the surface as a volcano, many people think it's ugly and dangerous, but other people think that it's beautiful.

We all know that a lot of people think the surface of the earth is ugly, and they have given up hope that people can change it, but the truth is that, the world is beautiful and we can change it.

You are beautiful and the people on your earth are represented as your brain. Your brain needs to tell you to look at yourself and to say that you are beautiful. You can change your mindset to tell you that you don't care what other people say, all that matters is what you say.

Always remember that :)

7 0

2 years ago

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Squandering Sam has $1,050 in his bank account. Every week he withdraws $40 to buy scratch off tickets. Saving Sally doesn’t hav

shtirl [24]

Answer:

15 weeks

Step-by-step explanation:

Week 1: 1,050 ≠ 0

Week 2: 1,010 ≠ 35

Week 3: 970 ≠ 70

Week 4: 930 ≠ 105

Week 5: 890 ≠ 140

Week 6: 850 ≠ 175

Week 7: 810 ≠ 210

Week 8: 770 ≠ 245

Week 9: 730 ≠ 280

Week 10: 690 ≠ 315

Week 11: 650 ≠ 350

Week 12: 610 ≠ 385

Week 13: 570 ≠ 420

Week 14: 530 ≠ 455

Week 15: 490 = 490

4 0

2 years ago

if grant drove his car for 417 miles on 15 gallons of gas. how many miles per gallon does grants car get?

lara [203]

Answer:

27.8 per mile.

Step-by-step explanation:

417 divided by 15 equals 27.8 miles per gallon

miles/ gallon

/ = per

so

417/ 15

27.8 gallons

3 0

2 years ago

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What other information do you need in order to prove the triangles congruent using the SAS congruence postulate

iren [92.7K]

AC is perpendicular to BD.

<h3>Further explanation</h3>

We observe that both the ABC triangle and the ADC triangle have the same AC side length. Therefore we know that $\boxed{ \ \overline{AC} \cong \overline{AC} \ }$ is reflexive.
The length of the base of the triangle is the same, i.e., $\boxed{ \ \overline{BC} = \overline{CD} \ }$ .
In order to prove the triangles congruent using the SAS congruence postulate, we need the other information, namely $\boxed{ \ AC \bot BD \ }$ . Thus we get ∠ACB = ∠ACD = 90°.

Conclusions for the SAS Congruent Postulate from this problem:

$\boxed{ \ \overline{BC} = \overline{CD} \ }$
∠ACB = ∠ACD
$\boxed{ \ \overline{AC} = \overline{AC} \ }$

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The following is not other or additional information along with the reasons.

∠CBA = ∠CDA no, because that is AAS with ∠ACB = ∠ACD and $\boxed{ \ \overline{AC} \cong \overline{AC} \ }$
∠BAC = ∠DAC no, because that is ASA with $\boxed{ \ \overline{AC} \cong \overline{AC} \ }$ and ∠ACB = ∠ACD.
$\boxed{ \ \overline{BC} = \overline{CD} \ }$ no, because already marked.

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Notes

The SAS (Side-Angle-Side) postulate for the congruent triangles: two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle; the included angle properly represents the angle formed by two sides.
The ASA (Angle-Side-Angle) postulate for the congruent triangles: two angles and the included side of one triangle are congruent to two angles and the included side of another triangle; the included side properly represents the side between the vertices of the two angles.
The SSS (Side-Side-Side) postulate for the congruent triangles: all three sides in one triangle are congruent to the corresponding sides within the other.
The AAS (Angle-Angle-Side) postulate for the congruent triangles: two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.

<h3>Learn more</h3>

Which shows two triangles that are congruent by ASA? brainly.com/question/8876876
Which shows two triangles that are congruent by AAS brainly.com/question/3767125
About vertical and supplementary angles brainly.com/question/13096411

9 0

3 years ago

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Find the expression that represents the length of the hypotenuse of a right triangle whose legs measure m^2-n^2 and 2mn

My name is Ann [436]

$\bf c^2=a^2+b^2\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
------\\
a=m^2-n^2\\
b=2mn
\end{cases}\\\\\\ c^2=(m^2-n^2)^2+(\underline{2mn})^2
\\\\\\
c^2=m^4-2m^2n^2+n^4+\underline{2^2m^2n^2}
\\\\\\
c^2=m^4-2m^2n^2+n^4+{4m^2n^2}
\\\\\\
c^2=m^4+2m^2n^2+n^4\impliedby \textit{perfect square trinomial}
\\\\\\
c^2=(m^2+n^2)^2\implies c=\sqrt{(m^2+n^2)^2}\implies c=m^2+n^2$

7 0

3 years ago