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QveST [7]
3 years ago
14

Can someone show me the work for the problem 6x-9y=-2i am trying to put the problem in slope-intercept form

Mathematics
1 answer:
topjm [15]3 years ago
6 0
Slope intercept form is y=mx+c
6x-9y=-2
Solve for y,
-9y = -6x -2
y = (6/9)x + (2/9)
y = (2/3)x +(2/9)
Hence, the slope intercept form of the equation is y=(2/3)x + (2/9)
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How do i fin the answer to this problem<br> n5 • k5 • n-5 • k?
postnew [5]
To solve this question, remember to apply the exponential law, of multiplying powers with the same base, one must add the exponents.

n^5 • n^-5 • k^5 • k^1
n 5 + -5 • k^5 + 1
n ^0 • k ^6
1 • k^6
k^6.
7 0
4 years ago
Does anyone know please
Novay_Z [31]

Answer:

8 hours and 54 minuter

Step-by-step explanation:

1 hour is equal to 60 minutes

we have 8 hours and 0.9 hours

0.9*60=54 minutes

we have 8 hours and 54 minuter

7 0
3 years ago
Read 2 more answers
−2(−1 1/4) <br> in simplest form
jolli1 [7]

Answer:

11/4 is your answer.

Step-by-step explanation:

What you do is you have to times -2 and -11/4 together.

This gives you 22/8.

This can be reduced by 2 to get:

11/4 as your answer.

6 0
4 years ago
Read 2 more answers
When a force of 36 Newtons is applied to springs S1 and S2, the displacement of the springs is 6 centimeters and 9 cm, respectiv
lozanna [386]

Answer: 200 \frac{N}{m}

Step-by-step explanation:

Hooke's law establishes that the elongation of a spring is directly proportional to the modulus of the force F applied to it, as long as the spring is not permanently deformed:  

F=k \Delta x

Where:  

F=36 N

k is the elastic constant of the spring

\Delta x is the displacement of the spring after applying the force

In this case we have two springs with constants k_{1} and k_{2}, displacement \Delta x_{1}=6 cm \frac{1 m}{100 cm}=0.06 m and \Delta x_{2}=9 cm \frac{1 m}{100 cm}=0.09 m, and the same force is applied to both.

For spring 1:

k_{1}=\frac{F}{\Delta x_{1}}

k_{1}=\frac{36 N}{0.06 m}

k_{1}=600\frac{N}{m}

For spring 2:

k_{2}=\frac{F}{\Delta x_{2}}

k_{2}=\frac{36 N}{0.09 m}

k_{2}=400\frac{N}{m}

Calculating the difference between them:

k_{1}-k_{2}=600\frac{N}{m}-400\frac{N}{m}

Finally:

k_{1}-k_{2}=200\frac{N}{m}

8 0
3 years ago
Solve this equation by using the look inside method to rewrite the problem <br><br> -81 = 3(5 - 4r)
TEA [102]
-81=3(5-4r)
27=-(5-4r)
27=-5+4r
-4r=-5-27
-4r=-32
r=8

Hope my answer helped u :)
4 0
3 years ago
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