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fiasKO [112]
2 years ago
12

Pls help I need the answer

Mathematics
2 answers:
alexandr402 [8]2 years ago
8 0

Answer:

The first choice.

11Alexandr11 [23.1K]2 years ago
4 0

Answer:

First choice

Step-by-step explanation:

Let n = the number of candy “Same” (???) bought

each piece of candy is 0.25 so we can multiply that by n. We have 0.25n now. Since the total cost of the candy is 2, we can put the 0.25n = 2

The answer is the same as choice 1, making it correct.

I hope this helped and please mark me as brainliest!

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Please view this imagine & help meee:(
EleoNora [17]

Answer:

20: 9t+12

21: 18x

22: 105x+9

24: 156r

25: 3x+11

26: 25.2x

28: 56a

29: 1.5n

30: 13q

Step-by-step explanation:

hope this helped

brainliest please

6 0
3 years ago
Find x. Round to the nearest tenth if necessary.
snow_tiger [21]

Answer:

your answers are in the attachment

hope it helps...

Step-by-step explanation:

8 0
2 years ago
(17+4) + 9 = 17 + (4+9)
valina [46]
That's the associative property of addition

it is normally written as
(a+b)+c=a+(b+c)
which is like what you have
(17+4)+9=17+(4+9)
6 0
3 years ago
6. Sketch the region enclosed by the graphs of x =0, 6y-5x=0 and x+3y=21. Find the area
kow [346]
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h

1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6

Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50

3 0
3 years ago
Read 2 more answers
Evan's odometer reads 44,965.3 miles. His car is four years old. On average, how many miles does Evan drive each year? Round you
Digiron [165]
Evan drives about 11241 miles each year
5 0
3 years ago
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