3 years ago

Find the product. (3x 2 - 5x + 3)(3x - 2)

Mathematics

1 answer:

Romashka [77]3 years ago

7 0

Answer:

9x^3-21x^2+19x-6

Step-by-step explanation:

First you have to distribute the first equation into the second since the two are being multiplied:

(3x^2-5x+3)(3x-2)

9x^3-6x^2-15^2+10x+9x-6

(simplify)

9x^3-21x^2+19x-6

You might be interested in

I thought it was if question but it is just 9

mafiozo [28]

Answer:

17-d=5

Step-by-step explanation:

Hope this helps :)

8 0

3 years ago

Read 2 more answers

Solve for N<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B12%7D%20%20%3D%20%5Cfrac%7B3%7D%7Bn%7D%20" id="TexFormula1"

Dmitrij [34]

Answer:

n= 1.25

Step-by-step explanation:

multiply both sides by 3 giving you 1.25

8 0

3 years ago

You are running a concession stand at a basketball game. You are selling hot dogs and sodas. Each hot dog costs $1.50 and each s

irga5000 [103]

The answer is add 35 and 52 and you will get 87 which was supposed to be the amount sold

4 0

2 years ago

What is the slope of (12,10),(12,5)

cestrela7 [59]

5/0 UNDEFINED... The answer is a vertical line.

5 0

3 years ago

Read 2 more answers

What are the chances your flight will leave on time? Below are a histogram and summary statistics for the percentage of flights

Jet001 [13]

Answer:

80.0456< $\bar x$ <81.1210

Step-by-step explanation:

-Given the mean, $\bar y=80.5833$ and $s=2.77369$ , the confidence interval can be calculated using the formula:

$\bar x\pm z\times \frac{\sigma}{\sqrt{n}}$

#We substitute our values in the formula to solve for CI:

$=\bar x\pm z\times \frac{\sigma}{\sqrt{n}}\\\\=\bar y\pm z_{0.05}\times \frac{s}{\sqrt{72}}\\\\=80.5833\pm 1.645\times \frac{2.77369}{\sqrt{72}}\\\\=80.5833\pm0.5377\\\\=[80.0456,81.1210]$

Hence, the confidence interval lies between 80.0456 and 81.1210

4 0

3 years ago