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vladimir2022 [97]
2 years ago
7

If it is 120 miles and you travel 40 mph, how long will it take you to get to your destination

Mathematics
2 answers:
Readme [11.4K]2 years ago
5 0
It’s D it will take you 4 hours
skad [1K]2 years ago
4 0

D. 4 hours. I would like brainlies please, so I can reach my new rank EXPERT. Thanks ~Angel411.


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A die is rolled find the probability of rolling a multipul of 5​
Pavlova-9 [17]

Answer:

1/6

Step-by-step explanation:

It's 1/6 because the only multiple of 5 in a die is 5, so it will be 1/6.

3 0
3 years ago
Please Help me this is the first part of 4 in this question. I will be posting the other 3 shortly. I need the answer. This is v
Ket [755]

Answer:

y = 1/6x + 5

Step-by-step explanation:

-x + 6y = 30

6y = x + 30

y = 1/6x + 5

6 0
2 years ago
3. Vocabulary Give an example of two
myrzilka [38]
Are the inequalities x > 3 and 3 < x equivalent?

They both say that x must be larger than 3. No bickering here. So yep, they're equivalent.

Inequalities usually have a lot of solutions—in fact, infinitely many. Think about the inequality x > 3. This inequality states that "x must be larger than 3." Any number bigger than 3 is a solution to this inequality. That includes 3.001, 3.0001, 4, 5, 2 million, and every other number bigger than 3. We don't have time at the moment to name them all,
5 0
3 years ago
What is the vertex of the graph of y = 1/3 (x-9)2 + 5 Question 1 options: (9,5) (3,3) (3,5) (-9,5)
svlad2 [7]
ANSWER

The vertex of the graph of
y =  \frac{1}{3}  {(x - 9)}^{2}  + 5
is

(9,5)



EXPLANATION

The vertex form of a parabola is given by

y = a {(x - h)}^{2}  + k

where
V(h,k)
is the vertex of the parabola.


The function given to us is

y =  \frac{1}{3}  {(x - 9)}^{2}  + 5
This is already in the vertex form.


When we compare this to the general vertex form, we have,

a =  \frac{1}{3}

h = 9
and

k = 5


Therefore the vertex of the parabola is

V(9,5)

Hence the correct answer is option A.

7 0
3 years ago
Read 2 more answers
Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
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