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Veronika [31]
2 years ago
7

Fabric is on sale for these prices: orange, $3 per yard; blue, $4 per yard; yellow, $2.50 per yard; and white $1.50 per yard. Ir

ma needs to buy 3 different colors of fabric with a total length of 2 yards. She has a budget of $6. What fabrics could she buy?
Mathematics
1 answer:
faust18 [17]2 years ago
3 0

Answer:

Yellow White And Orange I pretty Sure!! Im sorry if this is not what you want! I can change it if so.

Step-by-step explanation:

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What is the Volume of the square pyramid? (Round to the nearest tenth as needed)
GrogVix [38]
<h3><u>given</u><u>:</u></h3>

base= 25mm

height= 28mm

<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>

the volume of the pyramid.

<h3><u>solution</u><u>:</u></h3>

v= a^2 h/3

v= 25^2 28/3

v= 5833.33333

v= 5833.3mm^3

8 0
1 year ago
Read 2 more answers
The lines represented by the equations y x = 2 and y = x<br> 2 are
Sloan [31]

Answer: Parallel

Step-by-step explanation:

3 0
2 years ago
Which value of x makes the equation 0.75(x + 20) = 2 + 0.5(x − 2) true?​
rodikova [14]
You’d have to solve your equations!

they’d be the same when x=-56

and when x=-56 they’d BOTH equal -27

8 0
2 years ago
Meg and Rosa played a game. The game lasted 35 minutes and ended at 10:20 a.m.
ANEK [815]

Answer:

9:45 am

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
Read 2 more answers
The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.
Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let \mu = <u><em>population mean score</em></u>

So, Null Hypothesis, H_0 : \mu \leq 29.5      {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, H_A : \mu > 29.5      {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean MCAT score = 32.2

            s = sample standard deviation = 4.2

            n = sample of students = 40

So, <u><em>the test statistics</em></u> =  \frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }  ~  t_3_9

                                    =  4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0
3 years ago
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