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2 years ago

Let's say I have a question asking me which would best suit the data set.

Mathematics

1 answer:

Zarrin [17]2 years ago

7 0

Wait doesn’t it tell you how to solve it tho

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Every month Jordan puts $14 into her bank account. Her grandma puts additional money into Jordan's bank account every month. Aft

vesna_86 [32]

Answer

D $48.00 u need to multiply 216 and 12 to get 48

8 0

2 years ago

The formulae for kinetic energy is E =-mv2.<br><br> Find the value of E when m= 900 and v=1.3,

RSB [31]

Answer: ΔKE = 760.5 Joules

Step-by-step explanation:

Isnt the formula for ΔKE = 0.5m*v^2???

Im not going to use that formula you gave me, its wrong.

900/2 = 450

1.3^2 = 1.69

450 x 1.69 = 760.5 Jules

This is also the wrong subject btw

8 0

2 years ago

Evaluate the expression for the given value of the variable. |b| + b^3 ; b = -2, please show work!

Katen [24]

So b=-2 so you plug b in

l(-2)l + (-2)^3.

The absolute value of -2 is just 2 so now it is

2 + (-2)^3.

-2 * -2 is 4 but 4 * -2 is -8. So 2 + (-8) or 2 - 8 which comes to equal (-6) or negative six.

4 0

2 years ago

Suppose that X has a discrete uniform distribution on the integers 0 through 9. Determine the mean, variance, and standard devia

Anna35 [415]

With 10 integers available, $X$ has PMF

$\mathbb P(X=x)=\begin{cases}\dfrac1{10}&\text{for }0\le x\le9,x\in\mathbb Z\\\\0&\text{otherwise}\end{cases}$

We're interested in the statistics of the new random variable $Y=5X$ . To do this, we need to know the PMF for $Y$ . This isn't too hard to find.

$\mathbb P(Y=y)=\mathbb P(5X=y)=\mathbb P\left(X=\dfrac y5\right)$

Since the PMF for $X$ gives a value of $\dfrac1{10}$ whenever $x$ is an integer between 0 and 9, it follows that $\dfrac y5$ must also be an integer for the PMF to give the identical value of $\dfrac1{10}$ . This means

$\mathbb P(Y=y)=\begin{cases}\dfrac1{10}&\text{for }y\in\{0,5,\ldots,45\}\\\\0&\text{otherwise}\end{cases}$

Now the mean (expectation) is

$\mathbb E(Y)=\displaystyle\sum_yy\mathbb P(Y=y)=\frac1{10}\sum_{y\in\{0,\ldots,45\}}y$
$\mathbb E(Y)=\dfrac{225}{10}=22.5$

The variance would be

$\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb V(X)=\displaystyle\sum_yy^2\mathbb P(Y=y)-\mathbb E(Y)^2$
$\mathbb V(X)=\displaystyle\frac1{10}\sum_{y\in\{0,\ldots,45\}}y^2-\left(\frac{225}{10}\right)^2$
$\mathbb V(X)=\dfrac{7125}{10}-\dfrac{50625}{100}=206.25$

The standard deviation is the square root of the variance, so you have

$\sqrt{\mathbb V(X)}=\sqrt{206.25}\approx14.3614$

8 0

2 years ago

In a binomial experiment, if there are two possible outcomes and P(S) = 0.36, what is P(F)?

vampirchik [111]

Answer:

D. 0.64

Step-by-step explanation:

The reason I got this answer is because the problem tells us that there is a success rate of .36, so you would subtract .36 from 1 to get .64. The success rate and failure rate should always be equal to 1.

8 0

2 years ago