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Alex Ar [27]
3 years ago
8

Barium reacts with a polyatomic ion to form a compound with the general formula Ba3(X)2. What would be the most likely formula f

or the compound formed between sodium and the polyatomic ion X?
A. NaX
B. Na2X
C. Na2X2
D. Na3X
E. Na3X2
Chemistry
2 answers:
Citrus2011 [14]3 years ago
7 0

Answer:

Na3X  (Option Dis correct)

Explanation:

Ba + X → Ba3(X)2

Barium has an oxidation number of +2 = Ba^2+

Barium will form the compound Ba3(X)2 when it reacts with X

Ba3(X)2 = 3Ba^2+ + 2X^3-

X should be an element with oxidation number -3

When sodium will bind with X the following reaction will happen:

3Na+ + X^3- = Na3X

Since sodium has only 1 valence electron, we need 3 sodium atoms to bind 1 X atom.

Option D Na3X is correct

AfilCa [17]3 years ago
3 0

Answer:

D. Na₃X

Explanation:

We have the neutral compound Ba₃(X)₂. <em>The total charge (zero) is equal to the sum of the charges of the ions times the number of ions in the molecule</em>.

3 × qBa + 2 × qX = 0

3 × (+2) + 2 × qX = 0

2 × qX = -6

qX = -3

If we have the cation Na⁺ and X³⁻, a neutral molecule would require 3 Na⁺ and 1 X³⁻. The resulting compound is Na₃X.

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Diffusion is a general term referring to the net movement of atoms and molecules along a concentration gradient, from an area of
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Higher concentration to an area of lower concentration

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2. How many orbitals are in the following sublevels?
Lostsunrise [7]

Explanation:

The number of orbitals in the sublevels are given below:

     Sublevels                   Orbitals

        s                                  1

        p                                 3

        d                                 5

        f                                   7

a. ls       -  1 orbital

b. 5s      - 1 orbital

c. 4d     - 5 orbitals

d. 4f       - 7 orbitals

e. 7s       - 1 orbital

f. 3p       - 3 orbitals

g. Entire 5th principal energy level : for s, p ,  f  

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h. 6d   - 5

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Use the solubility rules to determine if:
xenn [34]

<u>Answer:</u>

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If both the reactants and products are in aqueous state, No reaction takes place.

$2 \mathrm{NaCl}(a q)+M g B r_{2}(a q)>M g C l_{2}(a q)+2 \mathrm{NaBr}(a q)(\mathrm{NO} \text { REACTION })$

All chlorides and Bromides are soluble except that of Ag, Hg and Pb.

Hence, No reaction takes place since all the reactants and products are in aqueous states.

${KOH}(a q)+{NaCl}(a q)>K C l(a q)+{NaOH}(a q)(\mathrm{NO} \text { REACTION })$

Salts  of Group IA are soluble. Hence No reaction takes place

$M g S(a q)+2 {NaOH}(a q)>M g(O H)_{2}(s)+N a_{2} S(a q)$

(REACTION TAKES PLACE)

All hydroxides are insoluble except that of Group IA, ammonium ion and  Group IIA down from Calcium.

Hence Reaction takes place with the formation of Mg(OH)_2 precipitate

5 0
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