All categories

3 years ago

How many nonreactive elements are there in the periodic table??

Chemistry

2 answers:

serg [7]3 years ago

7 0

Answer:

18 elements are nonreactive in the periodic table

pochemuha3 years ago

5 0

Answer:

Explanation:

All noble gases are nonreactive, these include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn).

You might be interested in

What is the name for the process by which gases spontaneously move from an area of higher concentration to one of lower concentr

AysviL [449]

The process by which gasses spontaneously move from an are with higher concentration to one of lower concentration is called diffusion. This process mainly occurs in gases and liquids. The end result of diffusion is called dynamic equilibrium. It is a complete mixing of the molecules of the gas.

7 0

3 years ago

Read 2 more answers

I need help with this question plz ASAP

Orlov [11]

Answer:

Explanation:

i farted

7 0

2 years ago

A chemist studies the reaction below. 2NO(g) + Cl2(g) 2NOCl(g) He performs three experiments using different concentrations and

Dmitry_Shevchenko [17]

Answer:

1. $Rate =k [NO]^{2}[Cl_{2}]$

2. $k= 0.42 \frac{L^{2}}{mol^{2}*s}$

Explanation:

$Rate =k [NO]^{m}[Cl_{2}]^{n}$

$Rate1 = k[0.4]^{m}[0.3]^{n}=0.02\\Rate 2=k [0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate1}{Rate2}=\frac{0.02}{0.08} =\frac{k[0.4]^{m}[0.3]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{1}{4} =(\frac{1}{2} )^{m},\\m=2$

$Rate3 =k [0.8]^{m}[0.6]^{n}=0.16\\Rate 2= k[0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate3}{Rate2}=\frac{0.16}{0.08} =\frac{k[0.8]^{m}[0.6]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{2}{1} =(\frac{2}{1} )^{n},\\n=1$

$Rate =k [NO]^{2}[Cl_{2}]^{1}$

$Rate =k [NO]^{2}[Cl_{2}]^{1}\\Rate 1=k [0.4]^{2}[0.3]^{1} =0.02\\k*0.16*0.3=0.02\\k=\frac{0.02}{0.16*0.3}=\frac{1}{8*(\frac{3}{10} )}=\frac{5}{12} = 0.42 \frac{L^{2}}{mol^{2}*s}$

6 0

2 years ago

Water freezes at____.

Aleks04 [339]

0 C
32 F
Water freezes

7 0

2 years ago

Write the formula and determine the percent by mass of the salt in barium hydroxide octahydrate *

user100 [1]

Answer:

315.51g/mol

Explanation:

137(33 + (16.00 + 1.01) 2 + 8 [1.01 (2) + 16.00] = 315.51g/mol

7 0

2 years ago