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frozen [14]
3 years ago
11

1. You have three molecules of glucose (3C6H12O6). How many carbon atoms do you have?. . A. 3. . B. 6. . C. 18. . D. 36. 2. Whic

h of the following is a homogenous mixture of two or more pure substances? . A. oxygen. B. water. C. air. D. alcohol.
Chemistry
2 answers:
Juliette [100K]3 years ago
6 0

Answer:

1. C. 18 atoms of carbon

2. C. Air

Explanation:

1. The formula of one molecule of glucose is

C_{6}H_{12}O_{6}

In this formula we have:

Carbon: 6 atoms

Hydrogen: 12 atoms

Oxygen: 6 atoms

if we have three glucose molecules, we have to multiply the formula (C_{6}H_{12}O_{6}) by three

3(C_{6}H_{12}O_{6})\\C_{18}H_{36}O_{18}

In this formula we have:

Carbon: 18 atoms

Hydrogen: 36 atoms

Oxygen: 18 atoms

2. A homogeneous mixture is the combination of 2 or more unidentifiable elements or substances within the solution.

Homogeneous mixtures are characterized by being uniform, this means that the elements that compose it are not distinguishable.

A. Oxygen is molecule O_{2}

B. Water is molecule compose by 2 elements H_{2}O

C. Air is a mixture of several gases.

D. Alcohol is compound of carbon, hydrogen and oxygen.C_{2}H{5}OH

Leviafan [203]3 years ago
3 0
One molecule of glucose has 6 carbon atoms. So if you have three molecules of glucose, simply multiply 3 by 6 carbon atoms. The correct answer is C. 18 Carbon atoms. 

The correct answer for the second questions is C. Air. A homogenous mixture is a mixture in which its components are uniformly distributed throughout the mixture. It has a sigle phase.
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A mixture of methane and carbon dioxide gases contains methane at a partial pressure of 431 mm Hg and carbon dioxide at a
KatRina [158]

Answer:

XCH₄ = 0.461

XCO₂ = 0.539

Explanation:

Step 1: Given data

  • Partial pressure of methane (pCH₄): 431 mmHg
  • Partial pressure of carbon dioxide (pCO₂): 504 mmHg

Step 2: Calculate the total pressure in the container

We will sum both partial pressures.

P = pCH₄ + pCO₂

P = 431 mmHg + 504 mmHg = 935 mmHg

Step 3: Calculate the mole fraction of each gas

We will use the following expression.

Xi = pi / P

XCH₄ = pCH₄/P = 431 mmHg/935 mmHg = 0.461

XCO₂ = pCO₂/P = 504 mmHg/935 mmHg = 0.539

3 0
3 years ago
Which change would increase the pressure exerted by a gas?
Gelneren [198K]

Answer:

C - raising the temperature of a gas

Explanation:

as you raise temperature, kinetic energy rises, and so does pressure

7 0
3 years ago
How many liters of O2 at 298 K and 1.00 bar are produced in 1.50 hr in an electrolytic cell operating at a current of 0.0200 A?
stellarik [79]

Answer: 0.0069L

Explanation:

2H2O(l) ---->O2(g) + 4H+(aq) + 4e-

no of moles= it/eF

NO of moles of O2 produced = (Current in Ampere x Time in second)/ (Faraday constant x Number of electrons required)

Moles of O2 produced = (0.02x (60 x 60X1.5 s)/(96485 x 4)

= 0.0002798 moles= 2.798x 10 ^-4moles

Using  ideal gas equation,

P V = n R T

Where, P is the pressure,

V is the volume,

n is the number of moles,

R is the gas constant, and T is the temperature

We have, 1 bar = 0.986923 atm

Substituting the values,

V = nRT/P = (2.798 x 10-4moles x 0.08205 L atm mol K x 298 K)/ 0.986923 atm = 0.0069L

Volume of O2 produced = 0.0069L

7 0
3 years ago
20.352 mL of chlorine under a pressure of 680. mm Hg are
Lunna [17]

Answer:

0.01144L or 1.144x10^-2L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 20.352 mL

P1 (initial pressure) = 680mmHg

P2 (final pressure) = 1210mmHg

V2 (final volume) =.?

Using the Boyle's law equation P1V1 = P2V2, the volume of the container can be obtained as follow:

P1V1 = P2V2

680 x 20.352 = 1210 x V2

Divide both side by 1210

V2 = (680 x 20.352)/1210

V2 = 11.44mL

Now we need to convert 11.44mL to L in order to obtain the desired result. This is illustrated below:

1000mL = 1 L

11.44mL = 11.44/1000 = 0.01144L

Therefore the volume of the container is 0.01144L or 1.144x10^-2L

7 0
3 years ago
Read 2 more answers
how much energy would it take to heat a section of the copper tubing that weights about 660.0 gram, from 12.93 degree Celsius to
expeople1 [14]

Answer:

                      Q  =  2647 J

Explanation:

                    Specific heat capacity is the amount of energy required by one Kg of a substance to raise its temperature by 1 °C.

In thermodynamics the equation used is as follow,

                                                 Q  =  m Cp ΔT

Where;

           Q  =  Heat  =  ?

           m  =  mass  =  660 g

           Cp  =  Specific Heat Capacity  =  0.3850 J.g⁻¹.°C⁻¹

           ΔT  =  Change in Temperature  =  23.35 °C - 12.93 °C  =  10.42 °C

Putting values in eq. 1,

                            Q  =  660 g × 0.3850 J.g⁻¹.°C⁻¹ ×  10.42 °C

                            Q  =  2647 J

8 0
4 years ago
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