What is tje equation for the linear function whose graph contains the points (2,5) and (3,0) ?
1 answer:
In order to find a slope, there is an equation:
Y2-Y1/X2-X1
X1=2
X2=3
Y1=5
Y2=0
0-5= -5
3-2=1
Since slope is written as Y/X, slope would be-5/1 or simply, -5.
Now, we need to find the y-intercept.
To do this, shift the original equation:
Original equation: y=-5x+b
Shifted equation: b=y+5x
Now, plug in one of the points.
Let's use (2,5)
b=5+5(2)
5*2=10
10+5=15
y-intercept=15
So, the full equation of the line would be:
y=-5x+15
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