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just olya [345]
3 years ago
5

What is tje equation for the linear function whose graph contains the points (2,5) and (3,0) ?

Mathematics
1 answer:
dolphi86 [110]3 years ago
4 0
In order to find a slope, there is an equation:

Y2-Y1/X2-X1

X1=2
X2=3
Y1=5
Y2=0

0-5= -5
3-2=1

Since slope is written as Y/X, slope would be-5/1 or simply, -5.

Now, we need to find the y-intercept.

To do this, shift the original equation:

Original equation: y=-5x+b

Shifted equation: b=y+5x

Now, plug in one of the points.

Let's use (2,5)

b=5+5(2)

5*2=10
10+5=15

y-intercept=15

So, the full equation of the line would be:

y=-5x+15
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Answer:

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The future value of the initial $300 deposit after 8 years is ...

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  A = $300(1 +0.0245/12)^(12·8) ≈ $364.89

The future value of the sum of $150 deposits monthly (at the beginning of the month) will be ...

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<em>Comment on account value</em>

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7 0
3 years ago
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Answer:

2.5

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The minimum value is the minimum y-value a function includes. In this case, since you can see the function is periodic (it repeats itself <em>periodically</em>, hence periodic) and the smallest y-value the function encounters is 2.5 (doesn't go below this value), the minimum y-value is 2.5. I hope this made sense. If not, feel free to let me know.

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Answer:

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