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3 years ago

Four more than a number is no more than thirteen

Mathematics

2 answers:

Gemiola [76]3 years ago

8 0

If x+4>13 then it would be x>9

zimovet [89]3 years ago

3 0

Four more than a number = x + 4;
No more than means using < in the equation;
So $x+4\ \textgreater \ 13$ is your equation.
$x+4\ \textgreater \ 13\\
x\ \textgreater \ 9$

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aniked [119]

Answer:

The answer is "Option a".

Step-by-step explanation:

In the given scenario, The appropriate test for the teaching profession's accomplishment pre and post-class would be the two-sample t-test with dependent samples, that's why choice "a" is correct.

7 0

3 years ago

Wich hotel costs the least per night ? :)

timofeeve [1]

Answer:

answer b

step - by - step explanation

Hotel A. per night charge is 64 $
Hotel B. per night charge is 60$
Hotel c. per night charge is 65$

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3 years ago

-12 + 3p = 3 <br> what does p equal

Svet_ta [14]

Answer:

p=5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

One night Puvi spent 1/3 of his money on dinner and then 1/4 of the remaining money on dessert. He then had just enough left so

arsen [322]

Answer:

Step-by-step explanation:

Cost of two tickets = 2 * 30 = £60

Let the amount with Puvi = £x

Money spent on dinner = (1/3)*x

$= \dfrac{1}{3}x$

$Remaining \ money =x - \dfrac{1}{3}x =\dfrac{3}{3}x-\dfrac{1}{3}x=\dfrac{2}{3}x$

$Money \ spent \ on \ dessert = \dfrac{1}{4} *\dfrac{2}{3}x =\dfrac{1}{6}x\\\\\\$

Total money - money spent on dinner - money spent on dessert = 60

$x -\dfrac{1}{3}x -\dfrac{1}{6}x=60\\\\\\\dfrac{6}{6}x-\dfrac{1*2}{3*2}-\dfrac{1}{6}x =60\\\\\\\dfrac{6}{6}x-\dfrac{2}{6}x-\dfrac{1}{6}x=60\\\\\\\dfrac{6-2-1}{12}x=60\\\\\\\dfrac{3}{12}x=60\\\\\\x=60*\dfrac{12}{3}=60*4=240$

Money that Puvi had at the start of the night = £ 240

8 0

3 years ago

HELP ME ITS TIMED AND I WILL GIVE BRAINLIEST!!!!!

Olegator [25]

To find the gradient of a line we first hv to find the formula

so Gradient=√X1-x2and √y1-y2

((-2,1) and (0,-5)) line 1

line 2(0,-1) and (1,0)

first we will work for line 1

X1 is -2

X2 is -0

Y1 is 1

Y2 is -1

so y=x-1

so we substitute the values

1--1=-2--0

so,

1+1=-2+0

2=-2

-0

So the equation 1 line 1 is not true

we will now go to equation 2 line 2

the equation is 3x+y=-5

we substitute the values

3(-2--0)+1--1=-5

3(-2)+-2=-5

-6+-2=-5

-8= -5

group like terms

Ur answer should look like this -3

So the answer is 3x+y=-5

7 0

3 years ago