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2 years ago

What is a name for the marked angle? Picture given

Mathematics

1 answer:

Zigmanuir [339]2 years ago

5 0

Answer:

L DAC

Step-by-step explanation:

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Which statement is true? Lisa has one and four twelves cups of grapes. Dawn has one and eleven twelves cups of grapes. Together

andrew11 [14]

Answer:

The fourth one: Gavin has one and thirteen fourteenths buckets of water. Daven has one and three fourteenths buckets of water. Together they have three and two fourteenths buckets of water.

Step-by-step explanation:

Gavin = 1 13/14

Daven = 1 3/14

1 13/14 + 1 3/14 = 2 16/14

2 16/14 = 3 2/14 = three and two fourteenths

8 0

3 years ago

Please help me with 6-9!!

kolezko [41]

I got C for 6 & 7. I haven't done this in a while so I don't know 8 & 9. I hope I helped!

4 0

3 years ago

Write an equation for a line that is parallel to 2x+5y=15 and passes through the point (-10, 3)

Lyrx [107]

Answer:

The equation of the line is,

$y = - \frac{2}{5} x - 1$

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

$2x + 5y = 15$

$5y = 15 - 2x$

$y = 3 - \frac{2}{5} x$

$y = - \frac{2}{3} x + 5$

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

$y = - \frac{ 2}{5}x + b$

$let \: x = - 10,y = 3$

$3 = - \frac{2}{5} ( - 10) + b$

$3 = 4 + b$

$3 - 4 = b$

$b = - 1$

3 0

3 years ago

Read 2 more answers

Find the interval(s) of upward concavity on this accumulation function.

maxonik [38]

$\displaystylef(x)=\int_{0}^{x^2}\sec^2(\sqrt{x})dx \\=\int_{0}^{\sqrt{x^2}}\sec^2(u)\cdot2udu \\=2\int_{0}^{\sqrt{x^2}}\sec^2(u)du \\=2\Big[u\tan(u)-\int\tan(u)du\Big]_{0}^{\sqrt{x^2}} \\=2\Big[u\tan(u)+\ln\Big(\mathrm{abs}(\cos(u))\Big)\Big]_0^x \\=2\Big(x\tan(x)+\dfrac{1}{2}\ln\Big(\cos^2(x)\Big)\Big) \\=2x\tan(x)+\ln(\cos^2(x))$

Hope this helps.

6 0

3 years ago

3(n-t) what is it?

g100num [7]

3(n-t) = 3n- 3t
It is you mean about ?

3 0

2 years ago