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Yanka [14]
3 years ago
12

One factor of x^3+x^2-14x-24 is x-4. find the remaining factor

Mathematics
2 answers:
Zanzabum3 years ago
8 0
Bananassbnskskakakaksisis
defon3 years ago
7 0

Answer:

x= -3

Step-by-step explanation:

3x+2x-14x-24=x-4

add 24 to both sides and subtract x to both sides

add them all up

-7x=21

Divide both sides by -7

x=3

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PLEASE HELP ME IM STUCK ON THIS QUESTION.
Vesna [10]

Answer:

You got it right. Triangle DAC

Step-by-step explanation:

Line segment DA is a perpendicular bisector(it cuts line segment CE perfectly in half making line segment AE an CA congruent. Since the triangle share line segment DA that makes them congruent by the SAS postulate

6 0
3 years ago
When trying to find a common denominator, can you multiply the denominators and get a common denominator?(example: 3/7 2/5
podryga [215]

Answer:

im pretty sure you have to cross muliply

but i learned in school what ever you do to the top do to the bottom

hope it helps

sorry no definet answer

Step-by-step explanation:

3 0
3 years ago
Lori creates the following design for a T-shirt.
kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

\Rightarrow FH \times HI=8.68

\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48  (∵ sides of the rectangle 1)

\Rightarrow EF+3.1= 5.4

\Rightarrow EF=2.3

\Rightarrow BH=2.3  (∵ sides of the rectangle 2)


BC = BH+HI+IC

\Rightarrow 11.7= 2.3+3.1+IC

\Rightarrow IC=6.3


The area of Rectangle 2,

=EB\times BH =2.8\times 2.3=6.44\ sq.in


The area of Triangle 2,

\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in


The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


6 0
3 years ago
Surveyors wished to know the distance across a lake between A and B. They measured the distance from B to C as 100 m and the ang
kherson [118]

Answer:

<h3>AB ≈ 70m</h3>

Step-by-step explanation:

Check the attachment for the diagram.

You can see from the diagram that it is a right angled triangle with opposite side AB and adjacent side BC. Using SOH, CAH, TOA trig identity to get the length of AB. According to TOA;

tan 35° = opposite/adjacent

tan 35° = AB/BC

tan 35° = AB/100

AB = 100tan35°

AB = 100 * 0.7002

AB = 70.02m

Hence the distance across a lake between A and B is approximately 70m

5 0
3 years ago
The 7th graders at Sunview Middle School were helping to renovate a playground for the kindergartners at a nearby elementary sch
VARVARA [1.3K]

Answer:

90 bags of sand

Step-by-step explanation:

9 feet × 1.5 = 13.5

12 feet × 1.5 = 18

Large pit area= 13.5 × 18 = 243ft squared

The small pit area=9 × 12 = 108ft squared

243 / 108 = 2.25 times larger

This means the large pit needs 2.25 times more sand.

40 × 2.25 = 90 bags of sand

5 0
3 years ago
Read 2 more answers
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