If the northern side has length x and the east and west sides have length y, then the cost of the fence is
<span>C = 12x + 12y + 6y </span>
<span>and the enclosed area is A = xy. </span>
<span>12x + 18y = 6000 </span>
<span>x = 500 - 1.5y </span>
<span>A = 500y - 1.5y^2 </span>
<span>A is maximized when y = 500/3. In which case x = 250. </span>
Answer:
a) Drag force = 5.67 N
b) Fraction of (drag force/weight) = 0.00964 = 0.964% (just less than 1%)
Step-by-step explanation:
Drag force is given by the expression
Drag force = CρAv²/2
C = Drag coefficient of air for an average human moving through air = 1.0
ρ = density of air = 1.2 kg/m³
A = Cross sectional Area of runner facing the air = 0.72 m²
v = velocity of the runner = (5km/23min) = (5000/23×60) = 3.623 m/s
Drag force = 1(1.2)(0.72)(3.623²)/2
Drag force = 5.67 N
b) Runner's weight = mg = 60×9.8 = 588 N
Fraction of (drag force/weight) = (5.67/588) = 0.00964 = 0.964% (just less than 1%)
x + 2y = 9
x + 3y = 13
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Solve for x in the first equation. Subtract 2y from both sides.
x = 9 - 2y
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Plug x into the second equation.
(9 - 2y) + 3y = 13
Combine like terms.
9 + y = 13
Subtract 9 from both sides.
y = 4
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Plug y back into the first equation.
x + 2(4) = 9
x + 8 = 9
Subtract 8 from both sides.
x = 1
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x = 1
y = 4
Answer:
Let the cost of orange be X and cost of cherry be y
3x + 9y = 78
8x + 4y = 58
Solving equation using elimination method
multiplying eq 1 with 8 and eq 2 with 3
8(3x + 9y ) = 78(8)
3( 8x + 4y) = 3(58)
24x + 72 y = 624
24x + 12y = 174
subtracting,
60 y = 450
y = 7.5
3x + 9(7.5) = 78
3x + 67.5 = 78
3x = 78 - 67.5
3x = 10.5
x = 3.5
<h2>Box of orange = $3.5 </h2><h2>Box of cherry = $7.5</h2>
Hello ;
<span>1/4+x <5/8
</span>x <5/8 - 1/4
x < 5/8 - 2/8
x < 3/8...(<span>the solution to the inequality)</span>
