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Mariulka [41]
3 years ago
10

I need help with this is my last one

Mathematics
1 answer:
Stells [14]3 years ago
3 0

Answer:

1. Quadrant 2

2. Quadrant 1

3. Quadrant 2

4. Quadrant 4

5. Quadrant 4

6. Quadrant 2

7. Quadrant 2

8. Quadrant 3

Step-by-step explanation:

For this problem, we just need to follow the pattern of positive and negatives associated with each quadrant.

The first quadrant (+, +)

The second quadrant (-, +)

The third quadrant (-, -)

The fourth quadrant (+, -)

Using these patterns we can state what order pair correlates to which quadrant.

(-2.5, 2.1) --> Q2

(1/2, 3/4) --> Q1

(-10, 13) --> Q2

(2.5, -5.5) --> Q4

(9, -10) --> Q4

(-12, 3.4) --> Q2

(-5/8, 5) --> Q2

(-6.4, -6.3) --> Q3

Cheers.

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Workers have been down the street installing two blinking red lights in front of the fire station. The two lights are always tur
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Answer:

After 88 seconds, they will blink together.

Step-by-step explanation:

Time after which the first light blinks = 8 seconds

Time after which the second light blinks = 22 seconds

Initially, both the lights blink together.

To find:

The time at which they will blink together again.

Solution:

Let us have a look at the time after which each light will blink.

First light will blink after:

8 s, 16 s, 24 s, 32 s, 40 s, 48 s, 56 s, 64 s, 72 s, 80 s, <em>88 s</em>, 96 s, 104 s, ......

Second light will blink after:

22 s, 44 s, 66 s, <em>88 s</em>, 110 s, .....

It can be seen that common time is 88 second, at which the both will blink together.

So, the answer is <em>88 s.</em>

<em></em>

This answer can also be computed by taking the LCM (Least Common Multiple) of both the numbers i.e. 8 and 22.

Using the factorization method:

8=\underline{2}\times 2\times 2

22=\underline{2}\times 11

Common is 2.

Therefore the LCM will be:

2\times 2\times2\times 11 = \bold{88}

So, the answer is <em>88 s.</em>

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Step-by-step explanation:

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Step-by-step explanation:

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