Answer:
D is correct. 
Step-by-step explanation:
We are given the root of the equation

If we are given solution of the equation then find equation using formula.
If a and b are the solution of equation then equation would be (x-a)(x-b)=0
Here, 
Equation form would be 
Now we simplify the above equation to get correct option.


So, D is correct. 
Answer: x= 42.3
Step-by-step explanation:
Sqrt a^2 + b^2 - (2ab)(cos 100)
Sqrt 25^2 + 30^2 - (2)(25)(30)(cos 100)
42.3
Answer
You did not give the whole picture, soory
Step-by-step explanation:
Answer:
0.0025 = 0.25% probability that both are defective
Step-by-step explanation:
For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
5 percent of these are defective.
This means that 
If two items are randomly selected as they come off the production line, what is the probability that both are defective
This is P(X = 2) when n = 2. So


0.0025 = 0.25% probability that both are defective