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2 years ago

Jaz was 43 inches tall. Eighteen months later,she was 52 inches tall. Determine the constant rate of change for jaz's height.

Mathematics

1 answer:

Dmitriy789 [7]2 years ago

6 0

She grew nine inches in eight months that is All I know

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Please help.<br> Algebra.

ladessa [460]

The answer is 1 bc the solution is (1,-3)

7 0

3 years ago

What is the sixth number in the Fibonacci sequence with the first two numbers 1 and 4?

Vanyuwa [196]

Answer:

Step-by-step explanation:

1 + 4 = 5 so we get 1 4 5

then 4+5 = 9, 1 4 5 9

5+9 = 14, 1 4 5 9 14

9+14 = 23, so

1 4 5 9 14 23

23 is the 6th number in this sequence

8 0

3 years ago

Eric invested 5000 dollars in the stock market. The value of his stock increased by 13%. a) what is the amount earned from this

blagie [28]

Answer:

$Earnings = 650$

$New\ Value = 5650$

Step-by-step explanation:

Given

$Amount = 5000$

$Rate = 13\%$

Solving (a): The earnings.

This is calculated as:

$Earnings = Amount * Rate$

$Earnings = 5000 * 13\%$

$Earnings = 650$

Solving (b): New Value

This is calculated as:

So, we have:

$New\ Value = Amount + Earnings$

$New\ Value = 5000 + 650$

$New\ Value = 5650$

4 0

2 years ago

4 1/3<br> What is the value of this equation?

sweet [91]

Answer:

4.33

Step-by-step explanation:

1/3=0.33 recuring

4 just eqauls 4

so you add 0.3 recuring to 4

and depending on significant figures it wants you round it ill assume it wants 3 and go 4.33

5 0

2 years ago

Please Help with angles!

777dan777 [17]

Step-by-step explanation:

003:

To solve this, we'll be using the Pythagorean theorem, $a^2+b^2=c^2$

$a^2+8^2=15^2\\a^2+64=225\\a^2=161\\a = \sqrt{161}$

004:

For the next couple questions we'll be using a fun rule called SOHCAHTOA, which stands for Sin (Opposite/Hypotenuse) Cos (Adjacent/Hypotenuse) Tan (Opposite/Adjacent). From this we can see that Tan θ is 8/ $\sqrt{161}$ .

005:

From this rule again, we can tell that sin Ф (Opposite/Hypotenuse) is going to be $\sqrt{161}$ /15.

Answer:

003: $\sqrt{161}$

004: 8/ $\sqrt{161}$

005: $\sqrt{161}$ /15

7 0

3 years ago