The circle is inscribed in Triangle AEC. Which are congruent line segments
2 answers:
Answer:
E-F and E-D
C-B and C-D
Step-by-step explanation:
The circle and triangle are as shown. The options are:
- A-B and C-B
- E-F and E-D
- E-D and C-D
- A-F and E-F
- C-B and C-D
By drawing radius lines from the center of the circle to the tangent points B, D, and F, we can divide the triangle into 3 kites. Therefore, only segments that are legs of the same kite are congruent. So the answer must be E-F and E-D, and C-B and C-D.
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Answer:
the proportion of days that are Sunny is 0.2
Step-by-step explanation:
Given the data in the question;
Using markov chain;
3 states; Sunny(1), Cloudy(2) and Rainy(3)
Now, based on given conditions, the transition matrix can be obtained in the following way;
so let the proportion of sunny, cloudy and rainy days be S, C and R respectively.
such that, from column 1
S = 0.25C + 0.25R -------------let this be equation 1
from column 2
0.5C = 0.5S + 0.25R
divided through by 0.5
C = S + 0.5R ---------------------- let this be equation 2
now putting equation 2 into equation;
S = 0.25(S + 0.5R) + 0.25R
S = 0.25S + 0.125R + 0.25R
S - 0.25S = 0.375R
0.75S = 0.375R
S = 0.375R / 0.75
S = 0.5R
Therefore,
from equation 2; C = S + 0.5R
input S = 0.5R
C = 0.5R + 0.5R
C = R
Now, we know that, the sum of the three proportion should be equal to one;
so
S + C + R = 1
since C = R and S = 0.5R
we substitute
0.5R + R + R = 1
2.5R = 1
R = 1/2.5
R = 0.4
Hence, the proportion of days that are Rainy is 0.4
C = R
C = 0.4
Hence, the proportion of days that are Cloudy is 0.4
S = 0.5R
S = 0.5(0.4)
S = 0.2
Hence, the proportion of days that are Sunny is 0.2
Answer:
A≈166.28in²
Step-by-step explanation:
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