Answer:
128 m
Explanation:
From the question given above, the following data were obtained:
Horizontal velocity (u) = 40 m/s
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Horizontal distance (s) =?
Next, we shall determine the time taken for the package to get to the ground.
This can be obtained as follow:
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
50 = ½ × 9.8 × t²
50 = 4.9 × t²
Divide both side by 4.9
t² = 50 / 4.9
t² = 10.2
Take the square root of both side
t = √10.2
t = 3.2 s
Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:
Horizontal velocity (u) = 40 m/s
Time (t) = 3.2 s
Horizontal distance (s) =?
s = ut
s = 40 × 3.2
s = 128 m
Therefore, the package will land at 128 m relative to the plane
compression forces can cause mountains to form or earthquakes to occur depending on how the earth's crust reacts to the force
We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
This question can easily be answered using a scientific calculator via complex mode using the form r∠α wherein r is the magnitude and α is the angle. So, incorporating vector addition through scientific calculator:
5∠53° + 8∠130 = 10.34∠101.9°
Therefore, the student's displacement is 10.34 m, 101.9°. In other words, the student is heading 78.1° (180 - 101.9 = 78.1) south of east.
Answer:
The ratio of the refractive indices of the liquids is 1.22
Solution:
Critical angle for A and B interface,
Critical angle for A and B interface,
Now,
From the relation in between the critical angle and refractive index:
(1)
where
n = rafractive index
= critical angle
Thus
For AB interface:
For AC interface:
Thus the ratio of the refractive indices of these liquids can be given as: