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2 years ago

find the mass of a ball on a roof 30 meters high, if the ball's gravitational potential energy is 58.8 joules

Physics

2 answers:

Taya2010 [7]2 years ago

4 0

Answer:

0.2 kg

Explanation:

Height of roof from the ground=h=30 m

Gravitational potential energy=P.E=58.8 J

We have to find the mass of the ball.

We know that

Gravitational potential energy of ball= mgh

Where g= $9.8 m/s^2$

Substitute the values

$58.8=m\times 9.8\times 30$

$58.8=294 m$

$m=\frac{58.8}{294}$

Using division property of equality

$m=0.2 kg$

Hence, the mass of ball=0.2 kg

Sidana [21]2 years ago

3 0

We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.

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AlekseyPX

Answer:

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Explanation:

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$v_2$ = Final Velocity of second car

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$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\\Rightarrow m_2v_2=m_{1}u_{1}+m_{2}u_{2}-m_{1}v_{1}\\\Rightarrow m_2v_2=120\times 14+m_2\times 0-(120\times -2)\\\Rightarrow m_2v_2=1920\\\Rightarrow m_2=\frac{1920}{v_2}$

Applying in the next equation

$v_2=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 120}{120+\frac{1920}{v_2}}\times 14+\frac{m_2-m_1}{m_1+m_2}\times 0\\\Rightarrow \left(120+\frac{1920}{v_2}\right)v_2=3360\\\Rightarrow 120v_2+1920=3360\\\Rightarrow v_2=\frac{3360-1920}{120}\\\Rightarrow v_2=12\ m/s$

$m_2=\frac{1920}{v_2}\\\Rightarrow m_2=\frac{1920}{12}\\\Rightarrow m_2=160\ kg$

Mass of second car = 160 kg

Velocity of second car = 12 m/s

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A horizontal wire is hung from the ceiling of a room by two massless strings. The wire has a length of 0.11 m and a mass of 0.01

AnnZ [28]

Answer:

Explanation:

The magnetic force acting horizontally will deflect the wire by angle φ from the vertical

Let T be the tension

T cosφ = mg

Tsinφ = Magnetic force

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Dividing

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Tension T = mg / cosφ

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