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1 year ago

How do you think this Eskimo nebula could affect Earth and

Physics

1 answer:

soldi70 [24.7K]1 year ago

5 0

Answer:

It does not affect. The closest nebula is the Orion Nebula at more than 1300 light years from Earth. It is so remote that nothing that happens there can influence the Earth. The only influence is to have beautiful colors and shapes and to let us dream one day to go there and explore them.

Explanation:

You might be interested in

Your eyes see different wavelengths of light as different ________.

zaharov [31]

Answer:

Its color

Explanation: I got it right

5 0

2 years ago

Looking straight downward into a rain puddle whose surface is covered with a thin film of gasoline, you notice a swirling patter

Ivanshal [37]

Answer:

Explanation:

Point beneath you forms a beautiful iridescent green

refractive index of Gasoline $n=1.38$

Wavelength of Green light is $\lambda =540\ nm$

Here light first traverse from air(n=1) to gasoline , it reflects from front surface of gasoline(n=1.38) so it suffers a phase change. After this light reflect from rear surface of gasoline and there is a decrease in refractive index(n=1.38 to n=1.33), so there is no phase change occurs .

For constructive interference

$2t=(m+\frac{1}{2})\cdot \frac{\lambda }{n}$

here t= thickness of gasoline film

n=refractive index

for $m=0$

$t=\frac{\lambda }{4n}$

$t=\frac{540}{4\times 1.38}$

$t=97.82\approx 98\ nm$

4 0

2 years ago

A rifle bullet with mass 8.00g strikes and embeds itself in a block with mass 0.992kg that rests on a frictionless, horizontal s

mafiozo [28]

Answer:

block velocity v = 0.09186 = 9.18 10⁻² m/s and speed bollet v₀ = 11.5 m / s

Explanation:

We will solve this problem using the concepts of the moment, let's try a system formed by the two bodies, the bullet and the block; In this system all scaffolds during the crash are internal, consequently, the moment is preserved.

Let's write the moment in two moments before the crash and after the crash, let's call the mass of the bullet (m) and the mass of the Block (M)

Before the crash

p₀ = m v₀ + 0

After the crash

$p_{f}$ = (m + M) v

p₀ = $p_{f}$

m v₀ = (m + M) v (1)

Now let's lock after the two bodies are joined, in this case the mechanical energy is conserved, write it in two moments after the crash and when you have the maximum compression of the spring

Initial

Em₀ = K = ½ m v2

Final

E $m_{f}$ = Ke = ½ k x2

Emo = E $m_{f}$

½ m v² = ½ k x²

v² = k/m x²

Let's look for the spring constant (k), with Hook's law

F = -k x

k = -F / x

k = - 0.75 / -0.25

k = 3 N / m

Let's calculate the speed

v = √(k/m) x

v = √ (3/8.00) 0.15

v = 0.09186 = 9.18 10⁻² m/s

This is the spped of the block plus bullet rsystem right after the crash

We substitute calculate in equation (1)

m v₀ = (m + M) v

v₀ = v (m + M) / m

v₀ = 0.09186 (0.008 + 0.992) /0.008

v₀ = 11.5 m / s

6 0

2 years ago

The decibel level of an orchestra is 90 db, and the violin section achieves a level of 80 dB. How does the sound intensity from

skad [1K]

Answer:

The difference in the decibel corresponses to a constant difference in the loudness perceived.

The refore the sound intensity from the orchestra is like 100 times that of the violin.

Explanation:

4 0

2 years ago

You need to know the height of a tower, but darkness obscures the ceiling. You note that a pendulum extending from the ceiling a

Sonja [21]

Answer:

L=55.9m

Explanation:

The equation for the period of a simple pendulum is:

$T=2\pi\sqrt{\frac{L}{g}}$

In our case what we know is the period and the acceleration of gravity, and we need to know the length of the pendulum, so we can write:

$L=(\frac{T}{2\pi})^2g$

Which for our values is:

$L=(\frac{15s}{2\pi})^2(9.81m/s^2)=55.9m$

6 0

2 years ago