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Yuki888 [10]
3 years ago
9

What is the following product? PLEASE HELP,I'M STRUGGLING SO MUCH!

Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0

(x√7 - 3√8 ) (x√7 - 3√8 )

To solve this question you must FOIL (First, Outside, Inside, Last) like so

First:

(x√7 - 3√8 ) (x√7 - 3√8 )

x√7 * x√7

For this you will multiply the numbers/variables on the out side together and separately multiply the values inside the square root together

(x*x)(√7*7)

x²√49

7x²

Outside:

(x√7 - 3√8 ) (x√7 - 3√8 )

x√7 * -3√8

(-3*x)(√7*8)

-3x√56

√56 can be further simplified to: 2√14

Now we have: -3x2√14 ---> -6x√14  

Inside:

(x√7 - 3√8 ) (x√7 - 3√8 )

The process is the exact same as in the "outside"

x√7 * -3√8

(-3*x)(√7*8)

-3x√56

√56 can be further simplified to: 2√14

Now we have: -3x2√14 ---> -6x√14

Last:

(x√7 - 3√8 ) (x√7 - 3√8 )

-3√8 * -3√8

(-3*-3)(√8*√8)

9√64

9*8

72

Now combine all the products of the FOIL together like so...

7x² - 6x√14 - 6x√14 + 72

Combine like terms:

 

7x² - 6x√14 - 6x√14 + 72

^^^When you add together square roots the number inside the radical stays the same, and you combine the numbers/variables attached to the radical on the outside

You selected the correct answer:

7x² -12x√14 + 72  

Hope this helped!

~Just a girl in love with Shawn Mendes

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~hope this helped, have a gr8 day/night my friend!~

Step-by-step explanation:

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Those would be classifications

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Tan 2A + sin 2A=4 tan A/(1 - tan4 A)​
stich3 [128]

Answer:

when \:  \\  \tan(2x)  =   \frac{2 \tan(x) }{1 -  {( \tan(x)) }^{2} }  \:  \: and \\  \sin(2x)  =  \frac{2 \tan(x) }{1 +  {( \tan(x)) }^{2} }  \\ then \\  \sin(2x)  +  \tan(2x)  =  \frac{2 \tan(x) }{1 -  {( \tan(x)) }^{2} }  +  \frac{2 \tan(x) }{1 +  {( \tan(x)) }^{2} }  \\  =  \frac{2 \tan(x)(1 +  {( \tan(x)) }^{2}  + 2 \tan(x) (1 -  {( \tan(x)) }^{2}  }{(1 +  {( \ \tan(x))  }^{2}(1 -  {( \tan(x)) }^{2}  }  \\  =  \frac{2 \tan(x) \times 2 }{1 -  {( \tan(x) }^{4} }  \\  =  \frac{4 \tan(x) }{1 -  {( \tan( \times ) )}^{4} }

Step-by-step explanation:

If you need any explanation. I can do it, my friend. you can communicate with me to that or any thing do you need in math

3 0
3 years ago
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