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Dahasolnce [82]
3 years ago
10

The following are the weights, in pounds, of some dogs at a kennel: 36, 45, 29, 39, 51, 49

Mathematics
1 answer:
MAXImum [283]3 years ago
5 0
What is the question...??
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A total of 70 tickets were sold for a concert and earn the organizers $804. If the cost of each ticket is either $10 or $12, how
crimeas [40]

Answer:

52 tickets cost $10 and 18 tickets cost $12

Step-by-step explanation:

10x+12y=804. (1)

x+y=70. (2)

From (2)

x=70-y

Substitute x=70-y into (1)

10x+12y=804

10(70-y)+12y=804

700-10y+12y=804

700+2y=804

2y=804-700

2y=104

y=104/2

y=52

Recall

x+y=70

x+52=70

x=70-52

x=18

52 tickets cost $10 and 18 tickets cost $12

5 0
3 years ago
Calculate the speed of a car that went a distance of 125 miles in 2 hours<br> time.
DerKrebs [107]

Answer:

62.5

Step-by-step explanation:

speed = distance / time taken

= 125/2

=62.5miles per hour

5 0
2 years ago
The resquest of the y'+6y=e^4t, y(0)=2
kotegsom [21]
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x). 
<span>Multiplying both sides of the equation by the integrating factor: </span>

<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>

<span>The left side is the derivative of ye^(6x), hence </span>

<span>d/dx[ye^(6x)] = e^(12x) </span>

<span>Integrating </span>

<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>

<span>y = (1/12)e^(6x) + ce^(-6x) </span>

<span>Use the initial condition y(0)=-8 to find c: </span>

<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>

<span>Hence </span>

<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
7 0
3 years ago
I need help with this maths homework please
valentinak56 [21]
I found this on another question made before

4 0
2 years ago
Where are my taurus’s At??
lozanna [386]

Answer:

im a scorpio but my sister in law is a taurus... :)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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