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3 years ago

If all of the diagonals are drawn from a vertex of a quadrilateral, how many triangles are formed? 1 2 3 4

Mathematics

2 answers:

Brrunno [24]3 years ago

6 0

Answer:

Step-by-step explanation:

i just took this on odyssey ware and made a 100

Archy [21]3 years ago

5 0

2 because if you have a square and draw a diagonal you get two triangles

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Jennifer Drive 265 miles in five hours what is her average rate of speed and miles per hour

iris [78.8K]

Answer:

53mph

Step-by-step explanation:

Divide 265 by 5, there is your answer.

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4 years ago

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Pls help or i will get an F<br> one easy question

Ne4ueva [31]

Answer:

p = 5.88/3 –.75

The original be price was $1.21 per lb pound

Step-by-step explanation:

To find the new price per pound, divide 5.88 by 3.

Then subtract .75 from the new be price to find the original price.

5.88/3 = 1.96

1.96 –.75 = 1.21

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3 years ago

Forever Fitness charges $50 a month and $15 for each exercise class you take. Peachtree Gym charges $75 a month and $10 for each

Anarel [89]

Answer:

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Step-by-step explanation:

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3 years ago

Find the value of x in the Parallelogram

andriy [413]

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7 0

3 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

4 years ago