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gavmur [86]
3 years ago
5

What is your slope of the line that contains the points (4,3) and (2,7)?

Mathematics
2 answers:
Nikolay [14]3 years ago
7 0

Answer:

The Correct Answer is: B

Step-by-step explanation:


MrRa [10]3 years ago
3 0

For this case we have that the slope of a line is given by:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Where (x_ {1}, y_ {1})\ and\ (x_ {2}, y_ {2}) are two points that belong to the line.

Then, having the following points:

(x_ {1}, y_ {1}) = (4,3)\\(x_ {2}, y_ {2}) = (2,7)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}\\m = \frac {7-3} {2-4}\\m = \frac {4} {- 2}\\m = -2

Thus, the slope is given bym = -2

Answer:

m = -2

Option B

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A movie theater complex gave a poll as viewers exited from two theaters showing the same film. They had a 20% response rate from
sp2606 [1]

Answer:

Let´s define the variables:

x = number of people in theater A

y = number of people in theater B

We know that a 20% (or 0.2 in decimal form) of the people in theater A answered the survey, then the number of people from theater A that answered the survey is: Na = 0.2*x

We know that a 30% (or 0.3 in decimal form) of the people in theater B answered the survey, then the number of people from theater B that answered the survey is: Nb = 0.3*y

There where 800 people in total (counting from the two theatres)

Then x + y = 800.

A) In this case we have:

Na = Nb

this means that:

0.2*x = 0.3*y

and we also have the equation:

x  + y = 800

To solve this, we need to isolate one variable in one of the equations, i will isolate x in the second equation:

x = 800 - y

And now we can replace this in the other equation to get:

0.2*(800 - y) = 0.3*y

We need to solve this for y:

160 - 0.2*y = 0.3*y

160 = 0.3*y + 0.2*y = 0.5*y

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Then there where 320 people in theater B, and:

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x = 440

y = 360

then:

Na = 0.2*440 = 88

In theater A, 88 people answered the survey.

Nb = 0.3*360 = 108

In theater B, 108 people answered the survey.

In total, 88 + 108 = 196 people answered the survey.

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Step-by-step explanation:

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