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docker41 [41]
3 years ago
15

Anna has a collection of 45 nickels and quarters worth $8.05. How many nickels does she have?

Mathematics
1 answer:
madreJ [45]3 years ago
3 0
It could be 1, I'm not really sure
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Bobby bought two shares of stock, which he sold for $96 each. If he had a profit of 20 percent on the sale of one of the shares
pashok25 [27]

Answer:

The correct option is c) a loss of $8.

Step-by-step explanation:

Consider the provided information.

If the selling price of two item is same and one item sold at a profit of x % and other at a loss of x % in that case total sale result loss:

To calculate the loss use the formula: Loss\ \%=(\frac{x}{10})^2\ \%

It is given that he had a profit of 20 percent on the sale of one of the shares but a loss of 20 percent on the sale of the other share, where the selling price is $96 each.

That means the total sale result will be a loss.

Now use the above formula by substitute x=20.

Loss\ \%=(\frac{20}{10})^2\ \%\\\\Loss\ \%=4\ \%

It is given that the sales price is $96 of each that means total sales price is:

$96+$96=$192

Let the cost price of the shares were x.

According to question: x-4% of x = 192

x-\frac{4}{100}\times x = 192\\\\x-0.04x = 192\\\\0.96x = 192\\x = 200

Hence, the cost price of the shares was 200.

Loss = Cost price -Sales price

Loss = $200 - $192

Loss = $8

Hence, the correct option is c) a loss of $8.

8 0
3 years ago
What is the solution of this system of linear equations? 3y=3/2x+6 1/2y-1/4x=3.
tensa zangetsu [6.8K]

Answer:

No solution

Step-by-step explanation:

Please, separate equations with a comma, or the word "and," or a semicolon.

Next, determine the LCD and multiply both equations by it, so as to elimiinate the fractional coefficients.

3y=3/2x+6 1/2y-1/4x=3

should be written as the system

   3y=(3/2)x+6         Use parentheses around the fraction for clarity

(1/2)y-(1/4)x=3            Same:  use parentheses

The LCDs here are 2 (for the first equation) and 4 (for the second equation).  Multiply the first equation by 2 to eliminate the fractions:

   3y=(3/2)x+6         →   6y = 3x + 12, and

4[ (1/2)y-(1/4)x=3 ]     →   2y  -  x   = 12

Let's use the substitution method to solve this system.  Solve the 2nd equation for x, obtaining x = 2y - 12.  Substitute 2y - 12 for x in the 1st equation 6y = 3x + 12:

6y = 3(2y - 12) + 12, or

6y = 6y - 36 + 12

This reduces to 0 = -24, which is never true.  Thus,

this system has NO solution.

 

5 0
3 years ago
What is the product (3a2 b4) (- 8b3)
Anvisha [2.4K]

Answer:

-24 a^2 b^7

Step-by-step explanation:

Simplify the following:

-8×3 a^2 b^4 b^3

Hint: | Combine products of like terms.

3 a^2 b^4 (-8) b^3 = 3 a^2 b^(4 + 3) (-8):

-8×3 a^2 b^(4 + 3)

Hint: | Evaluate 4 + 3.

4 + 3 = 7:

-8×3 a^2 b^7

Hint: | Multiply 3 and -8 together.

3 (-8) = -24:

Answer: -24 a^2 b^7

6 0
3 years ago
Leon wants to estimate the proportion of the seniors at his high school who like to watch football. He interviews a simple rando
cupoosta [38]

Answer:

Yes, the random conditions are met

Step-by-step explanation:

From the question, np^ = 32 and n(1 − p^) = 18.

Thus, we can say that:Yes, the random condition for finding confidence intervals is met because the values of np^ and n(1 − p^) are greater than 10.

Also, Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.

Confidence interval approach is valid if;

1) sample is a simple random sample

2) sample size is sufficiently large, which means that it includes at least 10 successes and 10 failures. In general a sample size of 30 is considered sufficient.

These two conditions are met by the sample described in the question.

So, Yes, the random conditions are met.

5 0
3 years ago
Please can someone explain and help me I am giving away 14 points the question is in the image
Tems11 [23]

Answer:

The area is 67.36 cm squared

Step-by-step explanation:

The height is 8.982. The base is 15. 8.982 * 15 = 134.73 / 2 = 67.36

5 0
2 years ago
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