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vredina [299]
3 years ago
7

. The function s(l) = 1.34 √l models the maximum speed s in knots for a sailboat with length l in feet at the waterline. a. Use

the model to find the length of a sailboat with a maximum speed of 12 knots. Round to the nearest foot.
Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

The length of the sailboat is 80 feet.

Step-by-step explanation:

The function  

s(l) = 1.34 \sqrt{l} ................ (1)  

models the maximum speed s in knots for a sailboat with length l in feet at the waterline.

So, using this model we have to find the length of a sailboat with a maximum speed of 12 knots.

Now, from equation (1) we get

12 = 1.34 \sqrt{l}

⇒ \sqrt{l} = 8.955

⇒ l = (8.955)^{2}  = 80 feet (Answer)

{The value is round to the nearest foot}

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g100num [7]

Answer:

Equivalent fractions

Step-by-step explanation:

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3 years ago
Aimi is making Valentine’s Day cards for everyone in her class. She plans to use a whole sheet of paper for each of her 6 closes
DaniilM [7]
34 - 6 = 28
28 x 8 = 224

After making the 6 whole sheet of paper cards for her closest friends Aimi will have 28 pieces of paper left.

Since she wants to use 1/8 of a sheet per valentine (think of it as one piece of paper can make 8 valentines) you can do 28 pieces of paper multiplied by 8 which gives you 224 valentines. 
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3 years ago
5x-4x+3=4x-12<br> A)4<br> B)5<br> C)-5<br> D)-4
slavikrds [6]

Answer:

B.) 5

Hope this helps :)

Step-by-step explanation:

5x - 4x + 3 = 4x - 12

x + 3 = 4x - 12

 +12               +12

x + 15 = 4x

-x         -x

15 = 3x

x = 5

6 0
3 years ago
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What is the answer to 5 divided by 1/3
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Step-by-step explanation:

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You bike 1 mile the first day of your​ training, 1.3 miles the second​ day, 1.9 miles the third​ day, and 3.1 miles the fourth d
JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

d_1=1 mi is the distance travelled during the 1st day

d_2=1.3 mi is the distance travelled during the 2nd day

d_3=1.9 mi is the distance travelled during the 3rd day

d_4=3.1 mi is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2

Which can be rewritten using the general formula:

d_{n+1}-d_n=2(d_n-d_{n-1})

This means that

d_{n+1}=d_n+2(d_n-d_{n-1})

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi

So, the  distance travelled on the 7th day is 19.9 miles.

7 0
4 years ago
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