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BlackZzzverrR [31]
3 years ago
12

What is the term for a fine grained soil deposited by the wind

Chemistry
1 answer:
balandron [24]3 years ago
4 0

I think it is called a loess. Please correct me if I am wrong.

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Draw the structure of an alkane or cycloalkane that has more than three but fewer than ten carbon atoms, and only primary hydrog
goldfiish [28.3K]

Answer:

The structures are shown in the figure.

Explanation:

The primary hydrogens are those which are attached to primary carbon.

Primary carbons are the carbons which are attached to only one carbon.

Primary carbons is bonded to three hydrogens.

In order to draw such structure we will draw structures which will have carbon with three hydrogens or no hydrogens (quaternary)

The structures are shown in the figure with clear marking.

7 0
2 years ago
A chemical equation is shown: C2H4 + O2 → CO2 + H2O According to the law of conservation of mass, how many atoms of oxygen exist
astraxan [27]

Answer:

6 oxygens on the product side

Explanation:

1) balance the equation:

C2H4 + 3O2 → 2CO2 + 2H2O

2) calculate the number of oxygens on the product side

2CO2=4

2H2O=2

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2 years ago
Answer that pls will give brainlist
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Answer:

1. went on the first manned launch during the Apollo mission

2. responsible for all spacecraft systems

3. 4500 hour

4. published All-American Boys

5. Joined back in space organization as a consultant to inspire next generation for mars

4 0
3 years ago
Which correctly lists three characteristics of minerals?
maria [59]

Answer:

The answer is A  hope this helps

Explanation:

6 0
3 years ago
Read 2 more answers
You have a 25.2 L sample of gas at 1.25 atm and 25.0 degrees Celsius. How many moles are present in this gas. For your answer, p
Elenna [48]

Answer:

  • <u>1.29 mol</u>

Explanation:

This is a direct application of the equation for ideal gases.

  • PV=nRT

Where:

  • P = pressure = 1.25 atm
  • V = volume = 25.2 liter
  • R = Universal constant of gases = 0.08206 atm-liter/K-mol
  • T = absolute temperature = 25.0ºC = 25 + 273.15 K = 298.15 K
  • n = number of moles

Solving for n:

  • n=\frac{PV}{RT}

Substituting:

n=\frac{1.25atm\times 25.2liter}{0.08206atm-liter/K-mol\times298.15K }\\\\n=1.29mol

8 0
2 years ago
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