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kotykmax [81]
2 years ago
11

For #61, What operations should I use?

Mathematics
1 answer:
kolbaska11 [484]2 years ago
3 0
There would be 432 trading cards. I know because to find the total number of cards you have to multiply 12*36 because on one pack there are 12 trading cards and you have 36 packs.12*36=432
There are 72 stickers because to find the total number of stickers you multiply 2*36 or 36*2 which equals 72
Trading cards =432
Stickers =72

Please thank this answer and mark it the brainliest
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Work out m and c for the line:<br> 2x + 3y +1=0 <br><br>m=<br>c =​
Sergio [31]

Answer:

m = - \frac{2}{3} , c = - \frac{1}{3}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

2x + 3y + 1 = 0 ( subtract 2x + 1 from both sides )

3y = - 2x - 1 ( divide terms by 3 )

y = - \frac{2}{3} x - \frac{1}{3} ← in slope- intercept form

with m = - \frac{2}{3} and c = - \frac{1}{3}

4 0
2 years ago
I need help I’ll give branliest
katovenus [111]

Answer:

A

Step-by-step explanation:

3 0
2 years ago
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A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
Use the equation y=3x-8 to find y when x=8
Stels [109]

Answer:  X = 8/3

Step-by-step explanation:

8 0
2 years ago
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What is the answer some one help please!!
scoray [572]
The correct answer is B
4 0
3 years ago
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