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3 years ago

Given g(x)=0.5x^2-5x+3.5, find g (4a)

Mathematics

1 answer:

grigory [225]3 years ago

4 0

Answer:

g(4a) = 8a^2 -20a +3.5

Step-by-step explanation:

Put 4a where x is and simplify.

g(x) = 0.5x^2 -5x +3.5

g(4a) = 0.5(4a)^2 -5(4a) +3.5

= 0.5(16a^2) -20a +3.5

g(4a) = 8a^2 -20a +3.5

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Sunny_sXe [5.5K]

Answer:

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

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Multiply the parentheses

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When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

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Distribute -x through the parentheses

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Using ${a}^{2} - {b}^{2} = (a + b)(a - b)$ , simplify the product

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Write 7x as a sum

$\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }$

Factor out X from the expression

$\frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x}$

Factor out 2 from the expression

$\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }$

Factor out x + 5 from the expression

$\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$

Hope this helps...

Best regards!!

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