Are you asking if this is greater than, less than, or equal to?
An arithmetic sequence has a common difference.
143 - 130 = 13
156 - 143 = 13
169 - 156 = 13
The common difference is 13.
a1 = 130
a2 = 130 + 13
a3 = 130 + 2 * 13
a4 = 130 + 3 * 13
...
an = 130 + (n - 1) * 13
an = 130 + 13(n - 1)
an = 130 + 13n - 13
an = 117 + 13n
an = 13n + 117
If Ike does not want more than 20 pounds in his backpack, this means he wants less than or equal to 20 pounds in his backpack. Because each paper costs 1/3 pound, this can be used as the rate of change and we can set up the following inequality:
1/3x < 20
To solve this inequality, we should divide both sides of the equation by 1/3.
x < 60
Because this inequality means that x is less than or equal to 60, the answer is that Ike can carry 60 papers in his backpack.
Hope this helps!
Answer:

Step-by-step explanation:
We want to find the inverse of
![y = \sqrt[3]{ \frac{x}{3} + 1}](https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7Bx%7D%7B3%7D%20%2B%201%7D%20)
We interchange x and y to get:
![x= \sqrt[3]{ \frac{y}{3} + 1}](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7By%7D%7B3%7D%20%2B%201%7D%20)
We solve for y;

Multiply through by 3

Subtract 1 from both sides:

Therefore the inverse is
