Answer:
y = -3x + 17
Step-by-step explanation:
In this question, you have to put the given equation into slope intercept form.
Slope-intercept form: y = mx + b
Solve:
y - 2= -3(x - 5)
Use the distributive property to distribute the -3 to the variables inside the parenthesis.
y - 2 = -3x + 15
Add 2 to both sides to get "y" by itself.
y = -3x + 17
The slope intercept form of the line would be y = -3x + 17
Problem 10
You are correct. The answer is choice C. The cm^3 notation represents cubic centimeters, which is a unit for volume. Think of a 1 cm by 1 cm by 1 cm cube.
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Problem 11
This problem is a bit strange. She borrows money ($100) but then it says she earns $300 per day. It makes no mention of her paying that $100 back, or when it's due back. I'll just assume that she keeps the $100 for the 12 days.
If that assumption is correct, then she'll have y = 300x+100 dollars after x days.
Plug in x = 0 and you'll get y = 100. Plug in x = 12 and you'll end up with y = 3700. Therefore, the two points on this graph are (0,100) and (12,3700).
The only window that has y = 3700 in it is the interval 
while the other windows are too small. So only choice D is the answer here. In other words, you'll have "yes" on choice D, and "no" on everything else.
Answer:
129 - 280 = 51.. So the answer is 51%
Answer:
The length is 13
Step-by-step explanation:
w+w+l+l= perimeter
if the length is 3m less than twice the width then let's do some math.
42 divided 2 =21. so the width and length of one side have to equal 21. For example, let's use 8 as the width. The length would be twice(16) minus three(13) 13 plus 8 is 21. WOW it equals half of it so no we know the length is 13 and the wdith is 8.
The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
<h3>How to determine the functions?</h3>
A quadratic function is represented as:
y = a(x - h)^2 + k
<u>Question #6</u>
The vertex of the graph is
(h, k) = (-1, 2)
So, we have:
y = a(x + 1)^2 + 2
The graph pass through the f(0) = -2
So, we have:
-2 = a(0 + 1)^2 + 2
Evaluate the like terms
a = -4
Substitute a = -4 in y = a(x + 1)^2 + 2
y = -4(x + 1)^2 + 2
<u>Question #7</u>
The vertex of the graph is
(h, k) = (2, 1)
So, we have:
y = a(x - 2)^2 + 1
The graph pass through (1, 3)
So, we have:
3 = a(1 - 2)^2 + 1
Evaluate the like terms
a = 2
Substitute a = 2 in y = a(x - 2)^2 + 1
y = 2(x - 2)^2 + 1
<u>Question #8</u>
The vertex of the graph is
(h, k) = (1, -2)
So, we have:
y = a(x - 1)^2 - 2
The graph pass through (0, -3)
So, we have:
-3 = a(0 - 1)^2 - 2
Evaluate the like terms
a = -1
Substitute a = -1 in y = a(x - 1)^2 - 2
y = -(x - 1)^2 - 2
Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
Read more about parabola at:
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