The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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This should help 10-1=9 9÷3=3 x=3
If 5 consecutive integers is 205,
then a + b + c + d + e = 205
but also, each integer is separated by a difference of 1
⇒ a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205
⇒ 5a + 10 = 205
⇒ 5a = 195
⇒ a = 39
∴ third term = 39 + 2
= 41
Answer:
(n/3)-10=6
Step-by-step explanation:
Let n be the number
Quotient of n and 3 is n/3
10 less that this is (n/3)-10=6
Answer:
No
Step-by-step explanation:
Since the rational number -0.4 is a negative, it cannot have a greater value than 1/3 since it is a positive.
Though, the rest of the sentence is true.
-0.4 > -2
-0.4 < 4/5
