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Leokris [45]
2 years ago
5

Hey guys- need help in this one

Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
8 0

Answer:

c

Step-by-step explanation:

x=5+i\sqrt{7} , y = 5-i\sqrt{7}\\ x^2-2xy+y^2=(x-y)^2\\ (x-y)^2=(2i\sqrt{7} )^2\\4.i^2.7\\-28

Galina-37 [17]2 years ago
7 0

Answer:

c

Step-by-step explanation:

given x = 5 + i\sqrt{7} then y = 5 - i\sqrt{7}

x² - 2xy + y² ← is a perfect square

= (x - y)² ← substitute values for x and y

= (5 + i\sqrt{7} - (5 - i\sqrt{7} )²

=  (5 + i\sqrt{7} - 5 + i\sqrt{7} )²

= (2i\sqrt{7} )²

= 2² × i² × (\sqrt{7} )²

= 4 × - 1 × 7

= - 28

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pogonyaev
I would have to say B. hope this helps
6 0
3 years ago
What is the equivalent expression of 12d4
dsp73

Answer:

2 same as question

Step-by-step explanation:

8 0
3 years ago
-4(9z -2)<br> hurrryyyyyyyyyyyyyyyyyyyyyyy
Sergio039 [100]
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3 years ago
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For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur
sergey [27]

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

          = (0.2)/(0.4)

P(A|B) =0.5

7 0
3 years ago
Can some body help me?
maksim [4K]

Answer:

24

Step-by-step explanation:

2(54-6x)=73-7x

108-12x=73-7x

108-73=-7x+12x

35=5x

x=7

UW=73-7x=73-7(7) = 73-49 = 24

3 0
3 years ago
Read 2 more answers
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