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Leokris [45]
2 years ago
5

Hey guys- need help in this one

Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
8 0

Answer:

c

Step-by-step explanation:

x=5+i\sqrt{7} , y = 5-i\sqrt{7}\\ x^2-2xy+y^2=(x-y)^2\\ (x-y)^2=(2i\sqrt{7} )^2\\4.i^2.7\\-28

Galina-37 [17]2 years ago
7 0

Answer:

c

Step-by-step explanation:

given x = 5 + i\sqrt{7} then y = 5 - i\sqrt{7}

x² - 2xy + y² ← is a perfect square

= (x - y)² ← substitute values for x and y

= (5 + i\sqrt{7} - (5 - i\sqrt{7} )²

=  (5 + i\sqrt{7} - 5 + i\sqrt{7} )²

= (2i\sqrt{7} )²

= 2² × i² × (\sqrt{7} )²

= 4 × - 1 × 7

= - 28

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