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Leokris [45]
2 years ago
5

Hey guys- need help in this one

Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
8 0

Answer:

c

Step-by-step explanation:

x=5+i\sqrt{7} , y = 5-i\sqrt{7}\\ x^2-2xy+y^2=(x-y)^2\\ (x-y)^2=(2i\sqrt{7} )^2\\4.i^2.7\\-28

Galina-37 [17]2 years ago
7 0

Answer:

c

Step-by-step explanation:

given x = 5 + i\sqrt{7} then y = 5 - i\sqrt{7}

x² - 2xy + y² ← is a perfect square

= (x - y)² ← substitute values for x and y

= (5 + i\sqrt{7} - (5 - i\sqrt{7} )²

=  (5 + i\sqrt{7} - 5 + i\sqrt{7} )²

= (2i\sqrt{7} )²

= 2² × i² × (\sqrt{7} )²

= 4 × - 1 × 7

= - 28

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kotegsom [21]
It is -3 to start off with, on Monday. On Tuesday morning it would be -3 - 2 degrees, = -5 degrees. By Tuesday evening it was 4 degrees lower than in the morning, so -5 - 4 degrees = -9 degrees on Tuesday evening.

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3 0
2 years ago
Read 2 more answers
Finding a parametric description of the solution set of a linear system is the same as solving the system.Choose the correct ans
Grace [21]

Answer:

The answer is "Choice B".

Step-by-step explanation:

Please find the complete question in the attached file.

In this question, in all choices, the choice (B) is Correct because in the declaration of the statement Only when the process has had at least another answer could a candidate solution for more than just a linear model explicitly uses a parametric description that's why the given statement is true.

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3 years ago
PLEASE HELP ME
monitta

Answer:

b

Step-by-step explanation:

7 0
2 years ago
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Is matrix multiplication comutative?
konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

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2 years ago
When data points group together in a cluster from the upper left-hand side of the xy axis to the lower right-hand side, what is
schepotkina [342]
Negative correlation

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