Question

What is the value of h in the figure below? In this diagram, ABAD - ACBD.

Answer 1

Answer:

h =12

Step-by-step explanation:

$In\: \triangle ABC, \: \angle ABC = 90\degree \: \&\:\\ BD\perp AC$

Therefore, by geometric mean property:

$BD = \sqrt {AD\times CD} \\h = \sqrt {(AC-CD) \times CD} \\h = \sqrt {(25-16) \times 16} \\h = \sqrt {9 \times 16} \\h = \sqrt {144} \\\huge \red {\boxed {h = 12}}$