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IrinaVladis [17]
4 years ago
15

What is the value of h in the figure below? In this diagram, ABAD - ACBD.

Mathematics
1 answer:
andreev551 [17]4 years ago
5 0

Answer:

h =12

Step-by-step explanation:

In\: \triangle ABC, \: \angle ABC = 90\degree \: \&\:\\ BD\perp AC

Therefore, by geometric mean property:

BD = \sqrt {AD\times CD} \\h = \sqrt {(AC-CD) \times CD} \\h = \sqrt {(25-16) \times 16} \\h = \sqrt {9 \times 16} \\h = \sqrt {144} \\\huge \red {\boxed {h = 12}} \\

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