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liberstina [14]
3 years ago
11

A rectangular exercise has a perimeter of 36 week the length of the mat is twice the width it right and solve and equation to de

termine the length of the feet of the mat then find the area in square feet of the mat
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
8 0

Answer:

Part a) The length of the rectangle is 12\ ft

Part b) The area of rectangle is 72\ ft^{2}

Step-by-step explanation:

step 1

Find the length

Let

L-----> the length of the rectangle

W---> the width of the rectangle

we know that

The perimeter of rectangle is

P=2(L+W)

P=36\ ft

so

36=2(L+W)

18=(L+W) ----> equation A

L=2W -----> equation B

substitute equation B in equation A

18=(2W+W)

solve for W

18=3W

W=18/3=6\ ft

Find the value of L

L=2(6)=12\ ft

step 2

Find the area

The area of rectangle is equal to

A=LW

substitute the values

A=(12)(6)=72\ ft^{2}

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A normal population has a mean of 19 and a standard deviation of 5.
dangina [55]

Answer:

a) Z = 1.2

b) 38.49% of the population is between 19 and 25.

c) 34.46% of the population is less than 17.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. If we need to find the probability that the measure is larger than X, it is 1 subtracted by this pvalue.

For this problem, we have that

A normal population has a mean of 19 and a standard deviation of 5, so \mu = 19, \sigma = 5.

(a) Compute the z value associated with 25

This is Z when X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 19}{5}

Z = 1.2

(b) What proportion of the population is between 19 and 25?

This is the pvalue of Z when X = 25 subtracted by the pvalue of Z when X = 19.

X = 25 has Z = 1.2, that has a pvalue of 0.8849.

X = 19 has Z = 0, that has a pvalue of 0.5000.

So 0.8849-0.500 = 0.3849 = 38.49% of the population is between 19 and 25.

(c) What proportion of the population is less than 17?

This is the pvalue of Z when X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 19}{5}

Z = -0.40

Z = -0.40 has a pvalue of 0.3446.

This means that 34.46% of the population is less than 17.

7 0
3 years ago
Prime factorisation of 49, 56,42 plz answer
ra1l [238]
49=7²
56=2³*7
42=2*3*7
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3 years ago
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Answer:

a) £6.70  b)6.4%

Step-by-step explanation:

a) 105.20-98.50=6.70

b)105.20-98.50/105.20 x100= 6.4%

i hope i got it right welp

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