A square is a quadrilateral with all four angles right angles and all four sides of the same length. ... Thus every square is a rectangle because it is a quadrilateral with all four angles right angles. However not every rectangle is a square, to be a square its sides must have the same length.
Answer:
4x^2 + 4x + 1=9
4x^2 + 4x - 8=0
Dividing both sides by 4
x^2 + x -2=0
It can be written as
x^2 + 2x - x - 2=0
x(x+2) -1(x+2)=0
taking (x+2) as common on LHS
Then, (x+2)(x-1)=0
Now first equate x+2=0 ie x=-2
then x-1=0 ie x=1
Therefore, x has two values(roots)
that is -2,1
Answer:
doesnt this count as plagirism
Step-by-step explanation:
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
If you convert the fractions to improper, you get 9/2 times 7/4. you can then just multiply the tops and bottoms and simplify! hope this helps
