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3 years ago

8

A box contains 48 tickets for six door prizes. Six tickets are drawn, and not replaced, to declare the winners. If serge purchas

es 8 tickets, determine the probability that he wins
a) the first prize
b) the first and second prizes
c) all six prizes

2 answers:

Lyrx [107]3 years ago

6 0

The tickets aren't replaced, so multiply the probabilities, decreasing the denominator each time.

a) 1/48
b) (1/48)(1/47)
c) (1/48)(1/47)(1/46)(1/45)(1/44)(1/43)

Sphinxa [80]3 years ago

6 0

A) $P(1st\ prize)=\frac{8}{48}$
b) $P(1st+2nd\ prizes)=\frac{8C2}{48C2}=.025$
c) $P(all\ 6\ prizes)=\frac{8C6}{48C6}=0.000002$

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<h3>QUESTION-2:</h3>

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<h3>Question-1:</h3>

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