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Tamiku [17]
3 years ago
8

A box contains 48 tickets for six door prizes. Six tickets are drawn, and not replaced, to declare the winners. If serge purchas

es 8 tickets, determine the probability that he wins
a) the first prize
b) the first and second prizes
c) all six prizes
Mathematics
2 answers:
Lyrx [107]3 years ago
6 0
The tickets aren't replaced, so multiply the probabilities, decreasing the  denominator each time.

a) 1/48
b) (1/48)(1/47)
c) (1/48)(1/47)(1/46)(1/45)(1/44)(1/43)
Sphinxa [80]3 years ago
6 0
A)P(1st\ prize)=\frac{8}{48}
b)P(1st+2nd\ prizes)=\frac{8C2}{48C2}=.025
c)P(all\ 6\ prizes)=\frac{8C6}{48C6}=0.000002
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natka813 [3]

Answer:

12 ( B )

Step-by-step explanation:

mode means the number that appears the most often

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Plug in 1 for x
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Three times a number, decreased by 8, is the same as twice the number, increased by 15. Find
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3 years ago
What is the arc measure of BDC in degrees?<br> (4k + 159)<br> P<br> (2k + 153)
andre [41]
<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

(4k + 159)^{\circ}

And another arc, let's call it FGH. measures:

(2k + 153)^{\circ}

If those arc are equal, then this equation is true:

(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3

Substituting k into the first equation:

\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}

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A: (450>/10)+5
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