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Tamiku [17]
3 years ago
8

A box contains 48 tickets for six door prizes. Six tickets are drawn, and not replaced, to declare the winners. If serge purchas

es 8 tickets, determine the probability that he wins
a) the first prize
b) the first and second prizes
c) all six prizes
Mathematics
2 answers:
Lyrx [107]3 years ago
6 0
The tickets aren't replaced, so multiply the probabilities, decreasing the  denominator each time.

a) 1/48
b) (1/48)(1/47)
c) (1/48)(1/47)(1/46)(1/45)(1/44)(1/43)
Sphinxa [80]3 years ago
6 0
A)P(1st\ prize)=\frac{8}{48}
b)P(1st+2nd\ prizes)=\frac{8C2}{48C2}=.025
c)P(all\ 6\ prizes)=\frac{8C6}{48C6}=0.000002
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Write the equation of a line that is parallel to {y=0.6x+3}y=0.6x+3y, equals, 0, point, 6, x, plus, 3 and that passes through th
Dominik [7]

y = 0.6x - 3.2  
The general form of the desired equation is 
y = mx + b
 where
 m = slope of the line
 b = y intercept of the line 
 If two lines are parallel, their slopes will be the same, Since the slope of the
given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line.
So our equation becomes:
 y = 0.6x + b 
 Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So
 y = 0.6x + b
 -5 = 0.6(-3) + b
 -5 = -1.8 + b
 -3.2 = b 
 So the desired equation is now 
y = 0.6x - 3.2
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3 years ago
Hiiiooo! Can someone please help me if you can’t see the picture I will gladly explain it in the comments!
Neporo4naja [7]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Min is twice as tall as her brother . If min is 5feet 3 inches tall how tall is her brother
liubo4ka [24]
5’3 is 63 inches since her brother is 1/3 larger so 63/3= 21 inches
3 0
3 years ago
Which side in WXYZ corresponds to OP in MNOP<br> A. XW<br> B. XY<br> C. YZ<br> D. MN
SOVA2 [1]

Answer:

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5 0
3 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
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