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vladimir1956 [14]
3 years ago
13

Let a=x^2+4. Use a to find the solutions for the following equation:

Mathematics
2 answers:
Kitty [74]3 years ago
7 0

Answer:

-2,0, 2(+)

Step-by-step explanation:

Helga [31]3 years ago
4 0
(x^2+4)^2 + 32 = 12x^2 + 48 .... a = x^2 + 4 
<span>(x^2 + 4)^2 + 32 = 12(x^2 + 4) </span>
<span>a^2 + 32 = 12a </span>
<span>a^2 - 12a + 32 = 0 </span>
<span>(a - 8)(a - 4) = 0 </span>
<span>a = 8 and a = 4 </span>

<span>for a = 8 ... 8 = x^2 + 4 ... x^2 = 4 ... x = +/- 2 </span>
<span>for a = 4 ... 4 = x^2 + 4 ... x^2 = 0 ... x = 0 </span>

<span>x = -2, 0, +2 so your answer is going to be e

</span>
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A forest has 800800800 pine trees, but a disease is introduced that kills \dfrac{1}{4} 4 1 ​ start fraction, 1, divided by, 4, e
snow_tiger [21]

This is a perfect example of exponential decay. In this case the growth factor should be represented by a fraction, and it is! This forest, starting out with apparently ( 800? ) pine trees, has a disease spreading, which kills 1 / 4th of each of the pine trees yearly. Therefore, the pine trees remaining should be 3 / 4.

Respectively 3 / 4 should be the growth factor, starting with 800 pine trees - the start value. This can be represented as such,

P( t ) = a( b )^t - where a = start value, b = growth factor, t = time ( <em>variable quantity</em> )

____

Thus, the function P( t ) = 800( \frac{3}{4} )^t can model this problem. The forest after t years should have P( t ) number of pine trees remaining.

3 0
3 years ago
If light travels at 10,000 km in 3.0 x 10² seconds,
eduard

Answer:

1000xm

Step-by-step explanation:

1 meter = 3.2808 feet, hence. 9.8424 x 10^8 feet in 1 second. 1 foot in x seconds. hence it takes 1 / (9.8424 x 10^8) = 0.10168 x 10^(-8) seconds. ➡️1km = 1000xm⬅️

4 0
2 years ago
Consider U = {x|x is a real number}. A = {x|x ∈ U and x + 2 &gt; 10} B = {x|x ∈ U and 2x &gt; 10} Which statements are true? 5 ∉
-Dominant- [34]

x+2 > 10 solves to x > 8 after we subtract 2 from both sides

So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.


Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.


----------------


Summarizing everything, we can say...

5 is not in set A. True

5 is in set B. False

6 is in set A. False

6 is not in set B. False

8 is not in set A. True

8 is in set B. True

9 is in set A. True

9 is not in set B. False


5 0
3 years ago
Read 2 more answers
193+y greater than and equal to 201
natta225 [31]
193+y greater than and equal to 201

Greater than or equal to = ≥

193 + y ≥ 201

193 + y greater than and equal to <span>= </span>193 + y ≥ 201
4 0
3 years ago
I need help againnnnn
JulijaS [17]
Hope this helps again! :)

6 0
3 years ago
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