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sertanlavr [38]
3 years ago
11

If you randomly select a beginner runner from the population have them run a 5k, what are the chances that they would finish it

between 25 and 27 minutes? That is, how many times, out of 100, would you randomly select someone that could run the 5k between 25 and 27 minutes? (Hint: use Appendix B.1 to answer this question. Start by calculating the z score for 25 and 27). Remember, you'll need to know the mean and standard deviation that you calculated for your population of runners. (Write a paragraph explaining, No Plagiarism!)
Time to complete 5k (in minutes):
21
21
22
22
23
23
23
24
24
24
24
24
25
25
25
26
26
27
27
Mathematics
1 answer:
Talja [164]3 years ago
8 0

Answer:

I dont know I’m just trynna get points sorry

Step-by-step explanation:

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In one U.S.​ city, the quadratic function f (x )equals 0.0039 x squared minus 0.42 x plus 36.79 models the​ median, or​ average,
Leviafan [203]

Answer:

The average age was minimum at 1954 and the average age is 25.5.

Step-by-step explanation:

The given quadratic function is

f(x)=0.0039x^2-0.42x+36.79

It models the​ median, or​ average, age,​ y, at which men were first married x years after 1900.

In the above equation leading coefficient is positive, so it is an upward parabola and vertex of an upward parabola, is point of minima.

We need to find the year in which the average age was at a minimum​.

If a quadratic polynomial is f(x)=ax^2+bx+c, then vertex is

Vertex=(-\dfrac{b}{2a},f(-\dfrac{b}{2a}))

-\dfrac{b}{2a}=-\dfrac{(-0.42)}{2(0.0039)}=53.846153\approx 54

54 years after 1900 is

1900+54=1954

Substitute x=54 in the given function.

f(54)=0.0039(54)^2-0.42(54)+36.79=25.4824\approx 25.5

Therefore, the average age was minimum at 1954 and the average age is 25.5.

8 0
3 years ago
PLEASE HELP! 25 POINTS <br><br> listen the question number then answer
frutty [35]

Answer: <

Explantion:

8*4-2(4)=24

5(10-4)=30, because you factor the 5 into 10 and 4 so

50-20=30

The second one you want will be integers.

7 0
4 years ago
Read 2 more answers
A(t) = (t – k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.
mr Goodwill [35]

the absolute value of the product of the zeros of a is -108 .

<u>Step-by-step explanation:</u>

Here we have , a(t) = (t - k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.  Given that a(2) = 0 . We need to find the  absolute value of the product of the zeros of a . Let's find out:

Equation every factor of a(t) to zero we get:

⇒ a(t) = (t - k)(t - 3)(t - 6)(t + 3) = 0

⇒ (t - k) =0\\(t - 3)=0\\(t - 6)=0\\(t + 3) = 0

⇒ t  =k\\t =3\\t = 6\\t =- 3

But , t=2 So , k=2  . Now , the absolute value of the product of the zeros of a is :

⇒ k(3)(6)(-3)

⇒ 2(3)(6)(-3)

⇒ -108

Therefore, the absolute value of the product of the zeros of a is -108 .

4 0
3 years ago
Circle the number sentences that show same addends in a different order 4 5=9 5 4=9 6 3=9.
prisoha [69]
4+5 and 5+4 because they use the same numbers but just reversed
5 0
3 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x=
Neporo4naja [7]

Answer:

x=19

Step-by-step explanation:

Set both equal to each other and then solve for x

7 0
3 years ago
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