A clothing store is having a sale on T-shirts. The first T-shirt you buy costs $7, and every additional shirt costs

Mathematics

2 answers:

ra1l [238]3 years ago

5 0

Answer: it is an Arithmetic sequence the formula is f(n) =7+5•(n-1)

Step-by-step explanation:

the first term is the price of a single shirt which is $7 the common difference is the price of any additional shirt, which is $5 therefore and explicit frma for the sequence would be f(n)=7+5•(n-1)

asambeis [7]3 years ago

4 0

Answer:

Is an arithmetic sequence

Step-by-step explanation:

This is an arithmetic sequence, because it is a sequence of numbers in which the common difference between consecutive terms is 5

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A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Minchanka [31]

<h2><u>Answer with explanation</u>:</h2>

Let $\mu$ be the distance traveled by deluxe tire .

As per given , we have

Null hypothesis : $H_0 : \mu \geq50000$

Alternative hypothesis : $H_a : \mu$

Since $H_a$ is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.

Test statistic : $z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

where, n= sample size

$\overline{x}$ = sample mean

$\mu$ = Population mean

$s$ =sample standard deviation

For $n= 31,\ \sigma=8000,\ \overline{x}=46,800\ \&\ s=46,800$ , we have

$z=\dfrac{46800-50000}{\dfrac{8000}{\sqrt{31}}}=-2.23$

By using z-value table,

P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23) [∵P(Z≤-z)=1-P(Z≤z)]

=1-0.9871=0.0129

Decision : Since p value (0.0129) < significance level (0.05), so we reject the null hypothesis .

[We reject the null hypothesis when p-value is less than the significance level .]

Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.

4 0

2 years ago

Pleas help me find the answer and show the work to this question

lions [1.4K]

Answer:

$Leg\ 1 = 8$