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Mars2501 [29]
4 years ago
8

A single zebrafish gene function was inactivated completely by mutation, and a zebrafish with this mutation had none of its norm

al horizontal stripes. For each of the following statements, indicate whether the statement is certainly true, certainly untrue or if there is insufficient information to decide. a. The normal gene function is required for the viability of the zebrafish. b. The normal gene function is required for the formation of stripes. c. The normal gene function is required to make the pigment deposited in the stripes. d. The gene is required in zebrafish only for stripe formation.
Biology
1 answer:
marissa [1.9K]4 years ago
6 0

Answer:a. The normal gene function is required for the viability of the zebrafish.

Explanation:

It is mentioned that if the gene responsible for forming stripes on its body is inactivated by mutation then fish without stripes will produced.

This will lead to the absence of phenotypic character that is strips on the fish. The other genes which are responsible for the survival of the fish will function normally thus this will be untrue that normal functioning of the gene required for expressing horizontal strips is also necessary for the survival and viability of the zebrafish.

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Why is it difficult to classify some bacteria and archaea from each other?
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4 years ago
According to the phylogenetic tree, which domains are more genetically related?
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8 0
3 years ago
What characteristic differentiates cardiac muscle cells from skeletal muscle cells?
suter [353]

Answer:

It's fibers

Explanation:

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4 years ago
Animals in the food chain need to eat less food than the animal in the previous level did to stay alive. True or False?
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8 0
3 years ago
Read 2 more answers
Imagine that you are performing a cross involving seed texture in garden pea plants. You cross true-breeding round and wrinkled
Tatiana [17]

Answer:

<h2>D)  610:190, round seeds:wrinkled seeds</h2>

Explanation:

Let round seed as R and wrinkled seed as r.

So the round is dominant (R) over wrinkled(r).

Hence , round is dominant and wrinkled is recessive rr.

Now cross between pure round (RR) and pure wrinkled (rr).

RR× rr

F1 offspring are:  Rr ( all)

Now cross between F1 offspring;

Rr × Rr

F2 are= RR, Rr, Rr and rr

RR and Rr = round

rr= wrinkled.

round to wrinkle ratio is= 3:1

So,  610:190; round seeds:wrinkled seeds  is the  expected result in the F2 progeny.

3 0
3 years ago
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