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lions [1.4K]
3 years ago
14

you buy a commemorative coin for $110. Each year t, the value V , of the coin increases by 4 %.Write a model that describes the

value of the coin after t years.How much is the coin worth 25 years later?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
4 0
The answer is $220. 110+4%x
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kotykmax [81]

Answer:

Step-by-step explanation:

6 0
2 years ago
Brian invests £13400 into his bank account.
Iteru [2.4K]

9514 1404 393

Answer:

  £17,755

Step-by-step explanation:

The formula for the balance of a simple-interest account is ...

  A = P(1 +rt) . . . . P is the amount invested, r is the annual rate, t is years

  A = £13400(1 + 0.065(5)) = £13400(1.325) = £17,755

Brian will have £17,755 after 5 years.

4 0
3 years ago
Determine the margin of error for a 90% confidence interval to estimate the population mean when s = 40 for the sample sizes bel
Ann [662]

Answer:

a) The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is 10.02.

Step-by-step explanation:

The t-distribution is used to solve this question:

a) n = 14

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7709

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.7709\frac{40}{\sqrt{14}} = 18.93

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) n = 28

27 df, T = 1.7033

M = T\frac{s}{\sqrt{n}} = 1.7033\frac{40}{\sqrt{28}} = 12.88

The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is

44 df, T = 1.6802

M = T\frac{s}{\sqrt{n}} = 1.6802\frac{40}{\sqrt{45}} = 10.02

The margin of error for a 90% confidence interval when n = 45 is 10.02.

3 0
2 years ago
Plz help me get the answer to these
Pavlova-9 [17]

Remove the brackets

-5a + 9b + 7a               combine -5a and 7a

7a - 5a + 9b

2a + 9b                        Answer

Don't go any further. There is nothing else to do. These are unlike terms and cannot be reduced or combined.

8 0
3 years ago
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Solve the equation: 8(x−3)+14=2(4x+5)
Murljashka [212]
The answer is No solution
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3 years ago
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