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musickatia [10]
3 years ago
8

Molecules of carbon dioxide are linear. What type of force exists betweenthese molecules?​

Chemistry
1 answer:
Vadim26 [7]3 years ago
7 0

London Dispersion forces

Explanation:

London dispersion forces exists between the molecules of CO₂. These are weak attractions found between non-polar (and polar) molecules(symmetrical molecules).

  • This attraction sometimes makes non-polar molecules polar.
  • This is because of the uneven charge distribution caused by the constant motion of its electrons.
  • A temporary dipole or instantaneous dipole induces the neighboring molecules to become distorted and forms dipoles as well.
  • The forces are the weakest of all electrical forces.

Learn more:

Intermolecular forces brainly.com/question/10107765

#learnwithBrainly

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Answer:

  • <u><em>The first statement is false:  a.At equilibrium, equal amounts of products and reactants are present. ΔG° is a function of Keq.</em></u>

Explanation:

When one part of a statement is false, the whole statement is false.

At <em>equilibrium,</em> the amounts of products and reactants does not have to be equal.

At equlibrium the rates of the forward reaction and the reverse reaction must be equal.

An equilibrium reaction may be represented by:

  • A + B ⇄ C + D

That represents two reactions:

  • Direct reaction: A + B → C + D (A and B yield C and D)

  • Reverse reaction: A + B ← C + D (C and D yield A and B: note that the arrow goes from right to left)

So, it is when the direct and the forward rates are equal that there is not net change in the amounts of all the species and so the reaction is is equilibrium).

As per the other statement, both parts are true:

  • When reactants become products, they do so through an intermediate transitrion state: when the reactants approach each other and collide with enough energy and appropiate position, the bonds start to break and the bonds of the products start to form. This is the transition state.

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According to Le Chatelier's principle , one method of driving the equilibrium towards the forward reaction is by removal of one of the products. In this case, if water is removed, the forward reaction is favoured.

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