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vovangra [49]
2 years ago
9

What is an example of an initiation phase for an addition

Chemistry
1 answer:
iren [92.7K]2 years ago
6 0

Answer:

H-O* + CH3-CH3 ----> H-O-CH2-CH2*

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The density of a metal is 10.5 g/cm3. If the mass of themetal
vitfil [10]

Answer:

11.7 mL

Explanation:

Density of a substance is given by the mass of the substance divided by the volume of the substance .

Hence , d = m / V

V = volume

m = mass ,  

d = density ,

From the question ,

The density of the metal = 10.5 g/cm³

The mass of the metal = 5.25 g

Hence , the volume can be calculated from the above formula , i.e. ,

d = m / V  

V = m / d

V = 5.25 g / 10.5 g/cm³

V = 0.5 cm³

Since , The unit 1 mL = 1 cm³

V = 0.5 mL

The vessel has 11.2 mL of water ,

The new volume becomes ,

11.2 mL +  0.5 mL = 11.7 mL

4 0
3 years ago
HelpUsing a 2-cm-thick piece of cardboard over a radiation source would be mosteffective for protecting against which type of ra
Lisa [10]
It would protect best against C) Alpha radiation, as Beta radiation is stopped by lighter metals such as aluminium, and Gamma radiation can only be stopped by heavier metals such as lead.
3 0
3 years ago
Read 2 more answers
Sodium carbonate (na2co3) is used to neutralize the sulfuric acid spill. how many kilograms of sodium carbonate must be added to
irga5000 [103]

Sodium carbonate is used to neutralised sulfuric acid, H₂SO₄. Sodium carbonate is the salt of stron base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:

Na₂CO₃ + H₂SO₄→ Na₂SO₄ + H₂CO₃

From balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of  H₂SO₄. Molar mass of Na₂CO₃= 106 g/mol=0.106 kg/mol and molar mass of H₂SO₄= 98 g/mol=0.098 kg/mol.

To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, to neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is=\frac{0.106 X 5.04 X 10^{3} }{0.098} kg= 5.451 X 10³ kg.

5 0
3 years ago
How many grams are in 2.54 x 10^23 molecules of CO2
Ivan

Answer:

=<em><u> 0.42 moles of CO2 </u></em>

Explanation:

From Avogadro's constant

6.02×10^23 molecules are in 1 mole of CO2

2.54×10^23 molecules will be in

=[(2.54×10^23) ÷ (6.02×10^23)]

= 0.42 moles of CO2

8 0
3 years ago
The pH of a solution that is formed by the neutralization of 1.0M H2SO4(aq) and 1.0 M KOH(aq) is closest to
pshichka [43]

Answer:

b) 7

Explanation:

The pH of a solution produced by the neutralization reaction between 1M of H₂SO₄ and KOH with 1M is closest to 7.

pH is a standard for measuring the acidity and alkalinity of a solution. A solution that is acidic will have a pH less than 7, a neutral solution will have pH of 7 and a basic solution will have pH greater than 7.

What is a neutralization reaction?

  • It is an acid-base reaction in which hydrogen and hydroxide ions combines to form water.
  • Also a salt results from the combination of the other ions.

In this reaction a base simply neutralizes an acid and the solution becomes neutral before it goes into completion.

Therefore, a neutral solution will have pH of 7 or close to it.

3 0
3 years ago
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