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3 years ago

What is an example of an initiation phase for an addition

Chemistry

1 answer:

iren [92.7K]3 years ago

6 0

Answer:

H-O* + CH3-CH3 ----> H-O-CH2-CH2*

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The reaction below will occur in a gaseous system at STP:

WARRIOR [948]

Answer:

V = 12.5 L

Explanation:

Given data:

Volume of NO = 15.0 L

Temperature and pressure = standard

Volume of nitrogen gas produced = ?

Solution:

Chemical equation:

6NO + 4NH₃ → 5N₂ + 6 H₂O

Number of moles of NO:

PV = nRT

n = PV/RT

n = 1 atm × 15.0 L / 0.0821 atm.L /mol.K × 273.15 K

n = 15.0 atm.L / 22.43 atm.L /mol

n = 0.67 mol

now we will compare the moles of No and nitrogen gas.

NO : N₂

6 : 5

0.67 : 5/6×0.67 = 0.56

Volume of nitrogen gas:

PV = nRT

1 atm × V = 0.56 mol × 0.0821 atm.L /mol.K × 273.15 K

V = 12.5 atm.L / 1 atm

V = 12.5 L

4 0

3 years ago

*explain your answer for brainliest

Over [174]

Answer:

3 mol Cl₂/2 mol AlCl₃ (three over two)

Step-by-step explanation:

Start with the balanced equation"

2Al + 3Cl₂⟶ 2AlCl₃

The steps in the calculation are

mass of AlCl₃ ⟶ moles of AlCl₃⟶ moles of Cl₂ ⟶ mass of Cl₂

The critical step is the conversion of moles.

You multiply the moles of AlCl₃ by a conversion factor to get moles of Al:

Moles of AlCl₃ × conversion factor = moles of Al.

The conversion factor is the molar ratio, and it uses the coefficients of the formulas in the balanced equation.

It is either (2 mol AlCl₃/3 mol Cl₂) or (3 mol Cl₂/2 mol AlCl₃).

You choose the one that has the desired units of the answer in the numerator.

We choose the second option, because it has the correct units.

For example,

$\text{0.2 mol AlCl}_{3} \times \frac{3\textbf{ mol Cl}_{2} }{ 2\text{ mol AlCl}_{3} } = 0.3\textbf{ mol Cl}_{2})$

Notice how the units "mol AlCl₃" cancel and the correct units appear in the answer.

If we had used the other conversion factor, we would have gotten the wrong units.

3 0

3 years ago