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vovangra [49]
2 years ago
9

What is an example of an initiation phase for an addition

Chemistry
1 answer:
iren [92.7K]2 years ago
6 0

Answer:

H-O* + CH3-CH3 ----> H-O-CH2-CH2*

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In the equation shown, what are the reactant(s)?
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C3H8 + O2 (please give me brainliest$
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Use the solubility generalizations on the information page to predict if one or more precipitates will form when aqueous solutio
neonofarm [45]

Answer:

3 (NH4)2SO4(aq) + 2 Al(NO3)3(aq) → 6 NH4NO3(aq) + Al2(SO4)3(aq)

Explanation:

In solubility rules, all ammonium and nitrates ions are solubles and all sulfates are soluble except the sulfates that are produced with Ca²⁺, Sr²⁺, Ba²⁺, Ag⁺ and Pb²⁺. That means the NH4NO3 and the Al2(SO4)3 produced are both <em>soluble and no precipitate is predicted. </em>

The reaction is:

<h3>3 (NH4)2SO4(aq) + 2 Al(NO3)3(aq) → 6 NH4NO3(aq) + Al2(SO4)3(aq)</h3>
6 0
2 years ago
Write a balanced half-reaction describing the reduction of aqueous vanadium(V) cations to aqueous vanadium(I) cations.
11Alexandr11 [23.1K]

Explanation:

Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.

Reduction takes place at the cathode.

In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.

The half reaction is :

V^{5+}(aq)+4e^- \rightarrow V^{1+}(aq)


5 0
3 years ago
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Which of the following is a group of different species living in the same approximate place
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What mass of AgCl is produced when 53.42 g of AgNO3 reacts with 14.19 g of NaCl?
Leya [2.2K]

Answer is: mass of silver chloride is 34,82 g.

Chemical reaction: AgNO₃ + NaCl → AgCl + NaNO₃.

<span>m(AgNO</span>₃) = 53,42 g..<span>
m(NaCl) = 14,19 g.
n(AgNO</span>₃) = m(AgNO₃) ÷ M(AgNO₃).<span>
n(AgNO</span>₃) = 53,42 g ÷ 169,87 g/mol.

n(AgNO₃) = 0,314 mol.

n(NaCl) = 14,19 g ÷ 58,4 g/mol.

n(NaCl) = 0,242 mol; limiting reactant.

From chemical reaction: n(NaCl) : n(AgCl) = 1 : 1.<span>
n</span>(AgCl)<span> = 0,242 mol.
m</span>(AgCl) = 0,252 mol · 143,32 g/mol.

m(AgCl) = 34,82 g.

7 0
2 years ago
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