Answer:
14.57g
Explanation:
Given parameters:
Mass of dish + ball = 15.6g
Initial volume of water in the cylinder = 26.7mL
Final volume of water in the cylinder = 38.9mL
Mass of dish = ?
Unknown
Mass of the ball = ?
Solution;
Since the mass of ball and dish is 15.6g,
Mass of the ball =Mass of ball + dish - mass of the dish
Insert the parameters and solve;
Mass of the ball = 15.6g - 1.03g = 14.57g
The oxidation state of the compound Mn (ClO4)3 is to be determined in this problem. For oxygen, the charge is 2-, the total considering its number of atoms is -24. Mn has a charge of +3. TO compute for Mn, we must achieve zero charge overall hence 3+3x-24=0 where x is the Cl charge. Cl charge, x is +7.
Explanation:
mass H2O2 = 55 mL(1.407 g/mL) = 80.85 g
molar mass H2O2 = 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol
moles H2O2 = 80.85 g/34.02 g/mol = 2.377 moles H2O2
For each mole of H2O2 you obtain 0.5 mole of O2 (see the equation).
moles O2 = 2.377 moles H2O2 (1 mole O2)/(2 moles H2O2) = 1.188 moles O2
Now, you need the temperature. If you are at STP (273 K, and 1.00 atm) then 1 mole of an ideal gas at STP has a volume of 22.4 L. Without temperature you are not really able to continue. I will assume you are at STP.
Volume O2 = 1.188 moles O2(22.4 L/mole) = 0.0530 L of O2.
which is 53 mL.
Answer:
The frequency of this light is
.
Explanation:
Wavelength of the light = ![\lambda = 430 nm=4.30\times 10^{-7} m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20430%20nm%3D4.30%5Ctimes%2010%5E%7B-7%7D%20m)
Speed of the light = c = ![= 3\times 10^8 m/s](https://tex.z-dn.net/?f=%3D%203%5Ctimes%2010%5E8%20m%2Fs)
Frequency of the light = ![\nu](https://tex.z-dn.net/?f=%5Cnu%20)
![\nu =\frac{c}{\lambda }](https://tex.z-dn.net/?f=%5Cnu%20%3D%5Cfrac%7Bc%7D%7B%5Clambda%20%7D)
![\nu =\frac{3\times 10^8 m/s}{4.30\times 10^{-7} m}=6.98\times 10^{14} s^{-1}](https://tex.z-dn.net/?f=%5Cnu%20%3D%5Cfrac%7B3%5Ctimes%2010%5E8%20m%2Fs%7D%7B4.30%5Ctimes%2010%5E%7B-7%7D%20m%7D%3D6.98%5Ctimes%2010%5E%7B14%7D%20s%5E%7B-1%7D)
The frequency of this light is
.