Question

What value of k makes the equation true? (5a^2b^3)(6a^kb)=30a^6b^4

Answer 1

The answer to your question is  4<span />

Answer 2

Answer:

k = 4

Step-by-step explanation:

Given: $(5a^2b^3)(6a^kb)=30a^6b^4$

Exponent law:

$x^m\cdot x^n=x^{m+n}$

$x^m\div x^n=x^{m-n}$

$5\cdot 6\cdot a^2\cdot a^k\cdot b^3\cdot b=30a^6b^4$

$30a^{2+k}b^{3+1}=30a^6b^4$

Compare the coefficient and power both sides

$30=30$

$a^{2+k}=a^6$

$b^4=b^4$

Exponent must be equal if base is equal.

Thus, 2+k = 6

k = 6 - 2

k = 4

Hence, The vaue of k is 4